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aleksley [76]
3 years ago
8

According to the theory of plate tectonics

Physics
1 answer:
Darya [45]3 years ago
8 0

Answer:

Alfred Wegener proposed the idea that earths lithospher is divided into tectonic plates.The theory was only accepted after he died.

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When ionic compounds are made using transition metals, ______________ are used in their naming.
forsale [732]

Answer:

Romen numerals

Explanation:

6 0
3 years ago
Two protons in a molecule are 4.40 10-10 m apart. Find the electric force exerted by one proton on the other.
Akimi4 [234]

Answer:

F = 1.19 x 10⁹ N

Explanation:

The electrostatic force between the charged particles is given by Colomb's Law as follows:

F = \frac{kq_{1}q_{2}}{r^{2}}

where,

F = Electrostatic force = ?

k = Colomb's constant = 9 x 10⁹ N.m²/C²

q₁ = q₂ = charge on proton = 1.6 x 10⁻¹⁹ C

r = distance between protons = 4.4 x 10⁻¹⁰ m

Therefore,

F = \frac{(9\ x\ 10^{9}\ Nm^{2}/C^{2})(1.6\ x\ 10^{-19}\ C)(1.6\ x\ 10^{-19}\ C)}{(4.4\ x\ 10^{-10})^{2}} \\\\

<u>F = 1.19 x 10⁹ N</u>

8 0
3 years ago
Does the speedometer of a car read average speed or instantaneous speed?
aleksandrvk [35]
Speedometer of car read instantaneous speed of course. Its because when you stop it instantaneous show 0. If speedometer show average speed there should be different value than 0 (much greater) just when you stop.
Maybe there are car with speedometer with average speed but the time from which the average is taken is extremely small. Its simply instantaneous speed.
8 0
3 years ago
Horse does 200 lb while pulling a sled for 3 mi .how much work does the horse do?
Anestetic [448]
Let's convert the quantities in SI units first.
The force exerted by the horse is
F=200 lb=889.6 N
and the distance covered is
d=3 mi=4828 m
Therefore, the work done by the horse is equal to the product between the force applied and the distance:
W=Fd=(889.6 N)(4828 m)=4.29 \cdot 10^6 J
4 0
3 years ago
A wheel 30 cm in diameter accelerates uniformly from 245 rpm to 380 rpm in 6.1 s . Part A How far will a point on the edge of th
jonny [76]

Answer:

A point on the edge of the wheel will travel 199.563 radians at the given time.

Explanation:

Given;

initial angular velocity of the wheel; \omega _i = 245 \ rev/\min = 245\ \frac{rev}{\min} \times \frac{2\pi}{1\  rev} \times \frac{1 \ \min}{60 \ s} = 25.66 \ rad/s

final angular velocity of the wheel;

\omega _f = 380 \ rev/\min = 380 \ \frac{rev}{\min} \times \frac{2\pi}{1\  rev} \times \frac{1 \ \min}{60 \ s} = 39.80 \ rad/s

radius of the wheel, d/2 = (30 cm ) / 2 = 15 cm = 0.15 m

time of motion, t = 6.1 s

The angular distance traveled by the edge of the wheel is calculated as;

\theta = (\frac{\omega_f + \omega_i}{2} )t\\\\\theta =  (\frac{39.8 + 25.66}{2} )\times 6.1\\\\\theta = 199.653 \ radian

Therefore, a point on the edge of the wheel will travel 199.563 radians at the given time.

6 0
3 years ago
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