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IgorLugansk [536]

2 years ago

12

The circumference of a circle is 31.4 inches. Enter the radius of the circle, in inches. Round your answer to the nearest whole

number.

1 answer:

Masteriza [31]2 years ago

3 0

Answer:

Should be 5 in.

Step-by-step explanation:

C=2*Pi*R

31.4=2*3.14*R

substitute 5 for radius= 2*5=10

10*3.14=31.4

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Directions on photo tyy! <3

Sunny_sXe [5.5K]

Picture 1: the colonists rights had been trampled over by the British, so they renamed the coercive rights and intolerable rights.
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5 0

2 years ago

PLEASE HELP ILL MARK BRAINLIEST !!!

Alexus [3.1K]

Answer:

a) the common difference is 20

b) $x_8=115 , x_{12}=195$

c) the common difference is -13

d) $a_{12}=52, a_{15}=13$

Step-by-step explanation:

a) what is the common difference of the sequence xn

Looking at the table, we get x_3=16, x_4=36 and x_5= 56

Deterring the common difference by subtracting x_4 from x_3 we get

36-16 =20

So, the common difference is 20

b) what is x_8? what is x_12

The formula used is: $x_n=x_1+(n-1)d$

We know common difference d= 20, we need to find $x_1$

Using $x_3=16$ we can find $x_1$

$x_n=x_1+(n-1)d\\x_3=x_1+(3-1)d\\15=x_1+2(20)\\15=x_1+40\\x_1=15-40\\x_1=-25$

So, We have $x_1 = -25$

Now finding $x_8$

$x_n=x_1+(n-1)d\\x_8=x_1+(8-1)d\\x_8=-25+7(20)\\x_8=-25+140\\x_8=115$

So, $\mathbf{x_8=115}$

Now finding $x_{12}$

$x_n=x_1+(n-1)d\\x_{12}=x_1+(12-1)d\\x_{12}=-25+11(20)\\x_{12}=-25+220\\x_{12}=195$

So, $\mathbf{x_{12}=195}$

c) what is the common difference of the sequence $a_m$

Looking at the table, we get a_7=104, a_8=91 and a_9= 78

Deterring the common difference by subtracting a_7 from a_8 we get

91-104 =-13

So, the common difference is -13

d) what is a_12? what is a_15?

The formula used is: $a_n=a_1+(n-1)d$

We know common difference d= -13, we need to find $a_1$

Using $a_7=104$ we can find $x_1$

$a_n=a_1+(n-1)d\\a_7=a_1+(7-1)d\\104=a_1+7(-13)\\104=a_1-91\\a_1=104+91\\a_1=195$

So, We have $a_1 = 195$

Now finding $a_{12}$ , put n=12

$a_n=a_1+(n-1)d\\a_{12}=a_1+(12-1)d\\a_{12}=195+11(-13)\\a_{12}=195-143\\a_{12}=52$

So, $\mathbf{a_{12}=52}$

Now finding $a_{15}$ , put n=15

$a_n=a_1+(n-1)d\\a_{15}=a_1+(15-1)d\\a_{15}=195+14(-13)\\a_{15}=195-182\\a_{15}=13$

So, $\mathbf{a_{15}=13}$

5 0

3 years ago

What is the Volume of the square pyramid? (Round to the nearest tenth as needed)

GrogVix [38]

<h3><u>given</u><u>:</u></h3>

base= 25mm

height= 28mm

<h3><u>to</u><u> </u><u>find</u><u>:</u></h3>

the volume of the pyramid.

<h3><u>solution</u><u>:</u></h3>

v= a^2 h/3

v= 25^2 28/3

v= 5833.33333

v= 5833.3mm^3

8 0

1 year ago

Read 2 more answers

What is the solution of the inequality shown below

Eduardwww [97]

Answer:

there is no inequality..

Step-by-step explanation:

5 0

2 years ago

Do you know the answer, ive been stuck for hours

nadya68 [22]

Answer:

Perpendicular H = 5.244 m (Approx)

Step-by-step explanation:

Given:

Hypotenuse = 9.4 m

Base = 7.8 m

Find:

Perpendicular H

Computation:

Perpendicular H = √Hypotenuse² - Base²

Perpendicular H = √9.4² - 7.8²

Perpendicular H = √Hypotenuse² - Base²

Perpendicular H = 5.244 m (Approx)

5 0

2 years ago