The values of m and n from the given equation are 1/4 and -2
<h3>Polynomial functions</h3>
Given the polynomial function below
f(x) = mx^4+2x^3-3x^2+nx-4
If the zeros are 2 and -2, hence;
0 = 16m+16-12+2n-4
0 = 16m-16+12-2n-4
_______________
16m+2n = 0
16m - 2n = 8
Subtract
2n+2n = -8
4n = -8
n = -2
Substitute for "m'
16m + 2(-2) = 0
16m = 4
m = 1/4
Hence the values of m and n from the given equation are 1/4 and -2
Learn more on polynomials here; brainly.com/question/2833285
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Answer: C
Explanation:
Since it’s a horizontal line and has mid point (1,3) then the y-intercept stays the same. So we eliminate a and b. We are left with c and d. But looking at d, their x-intercept is moving away from the mid point but c, their x-intercept is going in between the mid point so C is the answer
Answer:
Step-by-step explanation:
(-2 + x)/2= 4
-2 + x = 8
x = 10
(2 + y)/2 = -3
2 + y = -6
y = -8
(10, -8) for endpoint H
Answer:
12/25
Step-by-step explanation
First you count the amount of odd numbers there are.
Then whatever that number is , is you numerator.