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klasskru [66]
3 years ago
15

Terry wants to make a necklace with 50 beads she knows that 12 beads take up 5 inches of day how many beads fit on one foot a st

ring
Mathematics
1 answer:
Vanyuwa [196]3 years ago
6 0
<span>If you like my answer, please make me the brainliest answer! It means a lot. :)

1. Find how many beads per inch by dividing 12 by 5.

12 (beads) ÷ 5 (inches) = 2.4 beads per inch

2. We know that there are 12 inches in a foot, so we multiply 2.4 by 12.

2.4 × 12 = 28.8 beads!
</span>
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A roast turkey is taken from an oven when its temperature has reached 185 degrees F and is placed on a table in a room where the
Vedmedyk [2.9K]
(a) Using Newton's Law of Cooling, \dfrac{dT}{dt} = k(T - T_s), we have \dfrac{dT}{dt} = k(T - 75) where T is temperature after T minutes.
Separate by dividing both sides by T - 75 to get \dfrac{dT}{T - 75} = k dt. Integrate both sides to get \ln|T - 75| = kt + C.

Since T(0) = 185, we solve for C:
|185 - 75| = k(0) + C\ \Rightarrow\ C = \ln 110
So we get \ln|T - 75| = kt + \ln 110. Use T(30) = 150 to solve for k:
\ln| 150 - 75 | = 30k + \ln 110\ \Rightarrow\ \ln 75 - \ln 110= 30k \Rightarrow \\ k= \frac{1}{30}\ln (75/110) = \frac{1}{30}\ln(15/22)

So

\ln|T - 75| = kt + \ln 110 \Rightarrow |T - 75| = e^{kt + \ln110} \Rightarrow \\ \\&#10;|T - 75| = 110e^{kt} \Rightarrow T - 75 = \pm110e^{(1/30)\ln(15/22)t}  \Rightarrow \\&#10;T = 75 \pm110e^{(1/30)\ln(15/22)t}

But choose Positive because T > 75. Temp of turkey can't go under.

T(t) = 75 + 110e^{(1/30)\ln(15/22)t} \\&#10;T(45) = 75 + 110e^{(1/30)\ln(15/22)(45)}  = 136.929 \approx 137{}^{\circ}F

(b)

T(t) = 75 + 110e^{(1/30)\ln(15/22)t} = 75 + 110(15/22)^{t/30}  \\&#10;100 = 75 + 110(15/22)^{t/30}   \\&#10;25 = 110(15/22)^{t/30}  &#10;\frac{25}{110} = (15/22)^{t/30}   \\&#10;\ln(25/110) / ln(15/22) = t/30 \\&#10;t = 30\ln(25/110) / ln(15/22)  \approx 116\ \mathrm{min}

Dogs of the AMS.
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<span>When converting 3.68 the denominator will be 100.</span>
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