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Nat2105 [25]
3 years ago
14

Factor completely: x2 - 8x + 16

Mathematics
2 answers:
crimeas [40]3 years ago
7 0
x^2-8x+16=0\\\\x^2-2x\cdot4+4^2=0\ \ \ /use\ (a-b)^2=a^2-2ab+b^2/\\\\(x-4)^2=0\iff x-4=0\to\boxed{x=4}
katovenus [111]3 years ago
5 0
x^2 - 8x + 16 = 0\ \to\ a = 1\ ;\ b = -8\ ;\ c = 16

\frac{-b\pm \sqrt{b^2 - 4ac}}{2a} = \frac{8\pm \sqrt{64 - 4\cdot 1\cdot 16}}{2\cdot 1} = x_1 = 4\ ;\ x_2 = 4

x^2 - 8x + 16 = (x - 4)^2
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Is it a, b , c , or d?​
IrinaVladis [17]

The line has a positive slope. Let's look at all the slopes:

1) -3

2) -3

3) 3

4)3

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2) y = -3/2x + 5/2

We have to graph both of the lines now. The graphs are at the very bottom. Take a look at them. In the first one, the y-intercept is a negative and in the second one, the y-intercept is positive.

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3 years ago
If the probability of selecting, without replacement, 2 red marbles from a bag containing only red and blue marbles is 3 55 and
Marat540 [252]

Answer:

Step-by-step explanation:

Let T = the TOTAL number of marbles in the bag.

We are told that 3 of those marbles are red

P(select a red marble first) = 3/T

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So, P(select a red marble second) = 2/(T-1)

Okay, now let's use probability rules to answer the question....

P(select 2 red marbles) = P(select a red marble first AND select a red marble second)

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= 3/T x 2/(T-1)

= 6/(T² - T)

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So, we can write: 6/(T² - T) = 3/55

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So, EITHER T = 11 OR T = -10

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