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sertanlavr [38]

3 years ago

12

How to draw a point: w and z

1 answer:

trapecia [35]3 years ago

4 0

Please provide the proper image.

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Suppose a DVD costs $19 and a CD cost $14. Right in the inequality to find how many CDs you can buy along with one DVD if you ha

andrezito [222]

Answer: 19 + 14x ≤ 65

Explanation:

$19 is only added once because there is only one DVD purchased. $14 is added an unknown number of times, thus the variable X is included. We know that that the total number of dollars spent for both items is either less than or equal to 65. (Depending on your teacher, they may want you to write "19 + 14x < 65" if they want you to write the answer only for discrete numbers).

4 0

2 years ago

What is the value of y in this figure ?

Kruka [31]

Answer:

A

Step-by-step explanation:

if you subtract 54 from 180 you would get 126

5 0

3 years ago

2 · 32 + (3 · 2)2. i need the answer

vfiekz [6]

Answer: 76

Step-by-step explanation:

3 * 2 = 6

6* 2 = 12

2 * 32 = 64

12 + 64 = 76

4 0

3 years ago

the sides of a triangle are in the ratio 3: 4: 5 what is the lenghth of each side if the perimeter of the triangle is 90cm

ehidna [41]

3x+4x+5x=90

combine like terms

12x = 90

divide by 12

x = 7.5

sides: 3(7.5) ,4(7.5) ,5(7.5)

22.5, 30, 37.5

6 0

3 years ago

Find the zeros of y = x2 – 6x – 4 by completing the square.

katrin [286]

Answer:

The solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

Step-by-step explanation:

Given the function

$y\:=\:x^2\:-\:6x\:-\:4$

substitute y = 0 in the equation to determine the zeros

$0\:=\:x^2\:-\:6x\:-\:4$

Switch sides

$x^2-6x-4=0$

Add 4 to both sides

$x^2-6x-4+4=0+4$

Simplify

$x^2-6x=4$

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

$x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2$

$x^2-6x+\left(-3\right)^2=13$

Apply perfect square formula: (a-b)² = a²-2ab+b²

$\left(x-3\right)^2=13$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-3=\sqrt{13}$

Add 3 to both sides

$x-3+3=\sqrt{13}+3$

Simplify

$x=\sqrt{13}+3$

now solving

$x-3=-\sqrt{13}$

Add 3 to both sides

$x-3+3=-\sqrt{13}+3$

Simplify

$x=-\sqrt{13}+3$

Thus, the solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

4 0

3 years ago