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sertanlavr [38]
3 years ago
12

How to draw a point: w and z

Mathematics
1 answer:
trapecia [35]3 years ago
4 0
Please provide the proper image.
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Jimmy wrote the following proof to show that the diagnols of rectangle ABCD are congruent
ASHA 777 [7]

what option's do they give you. so I can help you


5 0
3 years ago
PLEASE HELP!! Look at picture for question thank you!!
tino4ka555 [31]

Answer:

5

Step-by-step explanation:

Since the two sides of the triangle have equal opposite angles , they will be equal .

Since sides opposite to equal angles are equal.

Using this concept ,

=> 3x -4 = 2x + 1

=> 3x - 2x = 4 + 1

=> x = 5

5 0
3 years ago
Read 2 more answers
PLEASE HELP <br> What is the value of y in this equilateral triangle?
Lelechka [254]

Answer:

5y-15=180

5y=180+15

5y=195

5y÷5y=195÷5

y=39

5 0
3 years ago
12b 40b^2 greatest common factor
SIZIF [17.4K]
12b and 40b^2.

12 and 40 have a greatest common factor of 4.

b^2 and b have a greatest common factor of b.

Therefore, the greatest common factor of the two expressions is 4b.
4 0
3 years ago
Find the particular solution of d2y/d x2<br> +4.<br> dx/Dy<br> +4y= 2 cos²x
Artyom0805 [142]

The solution to the equation are as follows.

y = c₁e^{\sqrt{-3 -sin²(x)x} } + c₂                e^{\sqrt{-3 -sin²(x)x} }

What is differential equation?

In arithmetic, a equation is associate equation that relates one or a lot of unknown functions and their derivatives.

Main body:

Find the first derivative.

dy/dx=re^{rx}

Find the second derivative.

d²y/dx² =r² e^{rx}

Substitute into the differential equation.

r²e^{rx}+4e^{rx}=cos ²x

Factor e^{rx}out of r²e^{rx}.

e^{rx}r²+4e^{rx}=cos²x

Factor e^{rx} out of 4e^{rx}.

e^{rx}r²+e^{rx}⋅4=cos²x

Factor out of e^{rx}r²+4e^{rx}

e^{rx}(r²+4)=cos²x

Since exponentials can never be zero, divide both sides by

e^{rx}r²+4=cos²x

Use the double-angle identity to transform

cos²x to 1−sin²(x).

r² +4=1−sin²(x)

Subtract 4 from both sides of the equation.

r²=1−sin²(x)−4

Simplify the right side.

r² = -3 -sin²x

r = √-3 -sin²x

By the principle of superposition, the general solution is a linear combination of the two solutions for a second order homogeneous linear differential equation.

y = c₁e^{\sqrt{-3 -sin²(x)x} } + c₂

Hence the differential solution is as follows.

To know more about differential equation , visit:

brainly.com/question/1164377

#SPJ1

6 0
2 years ago
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