Answer:
Attached below diagram of the eight diastereomers
The Isomer that reacts so slowly is DIASTEREOMER 8
Explanation:
The Isomer that reacts so slowly is DIASTEREOMER 8 in an E2 reaction and this is because no pair of chlorine and hydrogen atoms can assume the anti-periplanar orientation that is preferred in an E2 elimination
attached below is Diagram of the eight diastereomers ( screen shot from my drawing tool )
When a plant goes through photosynthesis, it uses light energy and converts it into chemical energy
Sodium is in group 1 so it has 1 valence electron (one electron in its outer shell). Sodium will be looking to lose its one valence electron in order to become more stable. Chlorine is in group 17 so it has 7 valence electrons, and therefor only needs to gain one valence electron to attain noble gas electron configuration (become stable with 8 valence electrons, just like the noble gases in group 18 have 8). Because the chlorine atom is trying to gain one electron, and the sodium atom is trying to lose one, sodium will give up its one valence electron to chlorine and the two atoms will form an ionic bond. Because chlorine is looking to gain just one electron and sodium is looking to lose the same number, the ratio of chlorine atoms to sodium atoms will be 1:1, one chlorine atom per one sodium atom.
In order to calculate the new freezing point, we must first find the depression. This is given by:
ΔT = Kf * b * i
where Kf is the cryscopic constant for the solvent, b is the molarity of the solution in moles per kilogram and i is the van't Hoff factor, which tells us how many ions will be released when a substance is dissolved.
Kf = 1.853, b = 1.5, i = 2 (Na⁺ and Cl⁻)
ΔT = 5.5 °C
The new freezing point will be 0 + 5.5
5.5 °C
