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Art [367]
3 years ago
7

Plz Help. write as polynomial-a²(3a-5)+4a(a²-a)​

Mathematics
1 answer:
Genrish500 [490]3 years ago
3 0

Answer:

a^3 + a^2

Step-by-step explanation:

Distribute the term left of each set of parentheses, then combine like terms.

-a²(3a - 5) + 4a(a² - a)​ =

= -3a^3 + 5a^2 + 4a^3 - 4a^2

= a^3 + a^2

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Viefleur [7K]

Answer:

y = 2/5 x - 18/5

Step-by-step explanation:

y = mx + b

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y = 2/5 x + b

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2 years ago
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dsp73

Answer:

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Step-by-step explanation:

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3 years ago
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Apply Crammer's Rule to find the solution to the following quations .2x + 3y = 1, 3x + y = 5​
Bond [772]

Answer:

The solution to the equation system given is:

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  • <u>y = -1</u>

Step-by-step explanation:

First, we must know the equations given:

  1. 2x + 3y = 1
  2. 3x + y = 5​

Following Crammer's Rule, we have the matrix form:

\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] =\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]

Now we solve using the determinants:

x=\frac{\left[\begin{array}{ccc}1&3\\5&1\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(1*1)-(5*3)}{(2*1)-(3*3)} = \frac{1-15}{2-9} =\frac{-14}{-7} = 2

y=\frac{\left[\begin{array}{ccc}2&1\\3&5\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =\frac{(2*5)-(3*1)}{(2*1)-(3*3)}=\frac{10-3}{2-9} =\frac{7}{-7}=-1

Now, we can find the answer which is x= 2 and y= -1, we can replace these values in the equation to confirm the results are right, with the first equation:

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  • 2(2) + 3(-1)= 1
  • 4 - 3 = 1
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And, with the second equation:

  • 3x + y = 5​
  • 3(2) + (-1) = 5
  • 6 - 1 = 5
  • 5 = 5

 

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3 years ago
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Answer:

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