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3 years ago

Let u = (1,2), v = (−3,4), and w = (5,0)

Mathematics

1 answer:

sergij07 [2.7K]3 years ago

7 0

Answer:

w-2u-v

Step-by-step explanation:

Given are three vectors u, v and w.

In R^2 we treat first element as x coordinate and 2nd element as y coordinate.

Thus we mark (1,2) in the I quadrant, (-3,4) in II quadrant and (5,0) on positive x axis 5 units form the origin.

b) $w=au+bv$

We have to find the values of a and b

$(5,0) = a(1,2)+b(-3,4)$ ]

Equate the corresponding terms

$5=a-3b\\0=2a+4b$

Divide II equation by 2 to get

$0=a+2b$

Eliminate a

-5 = 5b: b=-1

a=-2

Hence

w = 2u-v

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3 years ago

The quantity r varies jointly with t and u and inversely with s when t= -12, u= -7, and s= -4, r= -126. Find r when t= -8, u= 8,

vichka [17]

Answer:

r = 64

Step-by-step explanation:

r = (k*t*u)/s

Where,

k = constant of proportionality

t = -12,

u= -7,

s= -4,

r= -126.

r = (k*t*u)/s

-126 = (k*-12*-7)/-4

-126 * -4 = 84k

504 = 84k

k = 504/84

k = 6

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2 years ago

The number of bacteria in a culture is given by the function n(t) =950e^0.45t Where t is measured in hours A) what is the contin

tatiyna

Answer:

a) The continuous rate of growth of this bacterium population is 45%

b) Initial population of culture at t = 0 is 950 bacteria

c) number of bacterial culture contain at t = 5 is 9013 bacteria

Step-by-step explanation:

The number of bacteria in a culture is given by

n(t) = 950 $e^{0.45t}$

a) rate of growth is

Bacteria growth model N(t) = no $e^{rt}$

Where r is the growth rate

hence r = 0.45

= 45%

b) Initial population of culture at t = 0

n(0) = 950 $e^{0.45(0)}$

= 950 $e^{0}$

= 950 bacteria

c) number of bacterial culture contain at t = 5

n(5) = 950 $e^{0.45(5)}$

= 950 $e^{2.25}$

= 9013.35

= 9013 bacteria

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3 years ago