All categories

3 years ago

What’s the correct answer?

Mathematics

2 answers:

fredd [130]3 years ago

8 0

Answer:

Step-by-step explanation:

The question said the person bought a shirt which means 1 and 3 pairs of pants which means multiple but we don’t know how many so we substitute that ? for a x so 15 + 3x =117

yKpoI14uk [10]3 years ago

8 0

Answer:

Step-by-step explanation:

It is B because we do not know the price of the three pants but know that the total is 117 and the price of the t-shirt is $15

You might be interested in

CP= Rs. 9600, gain = 50/2%<br>16 find SP

nata0808 [166]

Shdhirh-828388-828283-828833

7 0

3 years ago

Can you guys help me with these to questions whoever answers this correct gets marked brainliest I need it before 6:00 pm please

Burka [1]

I only know the 2nd answer and it’s 101

6 0

3 years ago

Read 2 more answers

Richard and Teo have a combined age of 37. Richard is 13 years older than twice Teo's age. How old are Richard and Teo?

marysya [2.9K]

Answer:

Teo is 8 years old and Richard is 29 years old

Step-by-step explanation:

Let us solve the question

Assume that Teo is x years old

∵ Teo is x years old

∵ Richard is 13 years older than twice Teo's age

→ It means multiply x by 2, then add 13 to get the age of Richard

∴ Richard's age = 2x + 13

∵ Richard and Teo have a combined age of 37 years

→ Add their ages and equate the sum by 37

∴ x + 2x + 13 = 37

→ Add the like terms

∵ (x + 2x) + 13 = 37

∴ 3x + 13 = 37

→ Subtract 13 from both sides

∵ 3x + 13 - 13 = 37 - 13

∴ 3x = 24

→ Divide both sides by 3 to find x

∴ x = 8

∵ x represents Teo's age

∴ Teo is 8 years old

→ Substitute the value of x in the expression of Richard age to find his age

∵ Richard age = 2(8) + 13 = 16 + 13 = 29

∴ Richard is 29 years old

∴ Teo is 8 years old and Richard is 29 years old

8 0

3 years ago

Calculating conditional probabilities - random permutations. About The letters (a, b, c, d, e, f, g) are put in a random order.

Evgesh-ka [11]

A="b is in the middle"

B="c is to the right of b"

C="The letter def occur together in that order"

a) b can be in 7 places, but only one is the middle. So, P(A)=1/7

b) X=i, "b is in the i-th position"

Y=j, "c is in the j-th position"

$P(B)=\displaystyle\sum_{i=1}^{6}(P(X=i)\displaystyle\sum_{j=i+1}^{7}P(Y=j))=\displaystyle\sum_{i=1}^{6}\frac{1}{7}(\displaystyle\sum_{j=i+1}^{7}\frac{1}{6})=\frac{1}{42}\displaystyle\sum_{i=1}^{6}(\displaystyle\sum_{j=i+1}^{7}1)=\frac{6+5+4+3+2+1}{42}=\frac{1}{2}$

P(B)=1/2

c) X=i, "d is in the i-th position"

Y=j, "e is in the j-th position"

Z=k, "f is in the i-th position"

$P(C)=\displaystyle\sum_{i=1}^{5}( P(X=i)P(Y=i+1)P(Z=i+2))=\displaystyle\sum_{i=1}^{5}(\frac{1}{7}\times\frac{1}{6}\times\frac{1}{5})=\frac{1}{210}\displaystyle\sum_{i=1}^{5}(1)=\frac{1}{42}$

P(C)=1/42

P(A∩C)=2*(1/7*1/6*1/5*1/4)=1/420

$P(B\cap C)=\displaystyle\sum_{i=1}^{3} P(X=i)P(Y=i+1)P(Z=i+2)\displaystyle\sum_{j=i+3}^{6}P(V=j)P(W=j+1)=\displaystyle\sum_{i=1}^{3}\frac{1}{6}\frac{1}{7}\frac{1}{5}(\displaystyle\sum_{j=1+3}^{6}\frac{1}{4}\frac{1}{3})=1/420$

P(B∩A)=3*(1/7*1/6)=1/14

P(A|C)=P(A∩C)/P(C)=(1/420)/(1/42)=1/10

P(B|C)=P(B∩C)/P(C)=(1/420)/(1/42)=1/10

P(A|B)=P(B∩A)/P(B)=(1/14)/(1/2)=1/7

P(A∩B)=1/14

P(A)P(B)=(1/7)*(1/2)=1/14

A and B are independent

P(A∩C)=1/420

P(A)P(C)=(1/7)*(1/42)=1/294

A and C aren't independent

P(B∩C)=1/420

P(B)P(C)=(1/2)*(1/42)=1/84

B and C aren't independent

8 0

3 years ago

2y + 18 y + 39 Find y

uranmaximum [27]

Answer:

Step-by-step explanation: 2y+18 = y+39

y=21

3 0

3 years ago

Read 2 more answers