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FromTheMoon [43]
3 years ago
13

Dr. John Paul Stapp was U.S. Air Force officer who studied the effects of extreme deceleration on the human body. On December 10

, 1954, Stapp rode a rocket sled, accelerating from rest to a top speed of 282 m/s (1015 km/h) in 5.00 s, and was brought jarringly back to rest in only 1.40 s! Calculate his (a) acceleration and (b) deceleration. Express each in multiples of g (9.80 m/s2 ) by taking its ratio to the acceleration of gravity.
Physics
1 answer:
Mars2501 [29]3 years ago
6 0

Answer:

a) a=5.7551 \times g

b) d=20.5539\times g

Explanation:

Given:

  • speed of rocket initially, v_i=0\ m.s^{-1}
  • top speed of rocket after acceleration, v=282\ m.s^{-1}
  • time taken to get to the top speed, t_i=5\ m.s^{-1}
  • final speed of the rocket, v_f=0\ m.s^{-1}
  • time taken to get to the final speed after reaching the top speed, t_f=1.4\ s

Now the acceleration:

a=\frac{v-v_i}{t_i}

a=\frac{282-0}{5}

a=56.4\ m.s^{-2}

Now as a fraction of gravity:

a=\frac{56.4}{9.8}\times g

a=5.7551 \times g

Now, the deceleration:

d=\frac{0-282}{1.4}

d=201.4285\ m.s^{-2}

Now as a fraction of gravity:

d=\frac{201.4285}{9.8}\times g

d=20.5539\times g

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Engineers can determine properties of a structure that is modeled as a damped spring oscillator, such as a bridge, by applying a
Kazeer [188]

The value of spring constant and the oscillator's damping constant is

K= 6605.667008, b= 0.002884387

Explanation:

For Weakly damping spring oscillator

K/m = W_0^2     (at resonance)

K= mW_0^2

=0.206 * ( 2π * 28.5) ^2

=0.206 * (2π)^2 * (28.5)^2

K= 6605.667008

F = - bV

b= -F/V = -F/ -W_0 * m

=F/W_0 * m

= 0.438N / 2π * 28.5 * 0.848

b= 0.002884387

8 0
3 years ago
4. An object is thrown from from the ground upward with an initial speed of 3.75 m/s. How long will the object be in the air bef
Natali [406]

Answer:

Explanation:

There's an easy way to answer this and then an easier way. I'll do both since I'm not sure what you're doing this for: physics or calculus. Calculus is the easier way, btw.

Going with the physics version first, here's what we know:

a = -9.8 m/s/s

v₀ = 3.75 m/s

t = ??

That's not a whole lot...at least not enough to directly solve the problem. What we have to remember here is that at the max height of a parabolic path, the final velocity is 0. So we can add that to our info:

v = 0 m/s. Use the one-dimensional equation that utilizes all that info and allows us to solve for time:

v = v₀ +at and filling in:

0 = 3.75 + (-9.8)t and

-3.75 = -9.8t so

t = .38 seconds. This is how long it takes to get to its max height. Another thing we need to remember (which is why calculus is so much easier!) is that at the halfway point of a parabolic path (the max height), the object has traveled half the time it takes to make the whole trip. In other words, if .38 is how long it takes to go halfway, then 2(.38) is how long the whole trip takes:

2(.38) = .76 seconds. Now onto the calculus way:

The position function is

s(t)=-4.9t^2+3.75t The first derivative of this is the velocity function and, knowing that when the velocity is 0, the time is halfway gone, we will find the velocity function and then set it equal to 0 and solve for t:

v(t) = -9.8t + 3.75 and

0 = -9.8t + 3.75 and

-3.75 = -9.8t so

t = ,38 and multiply that by 2 to find the time the whole trip took:

2(.38) = .76 seconds.

6 0
3 years ago
A scientist counts the number of bacteria colonies growing in each of six lab dishes.
Nadusha1986 [10]

13 is the mode because it is the number that appears most often

:)

5 0
3 years ago
Read 2 more answers
High energy waves have short wave lengths, true or false?
Anna71 [15]
True, the wavelength dies down due to high frequency and low amptitude. 
5 0
3 years ago
The sun is about 150 million km away from earth. The rays of sunlight that reach earth’s atmosphere are best represented as ____
tangare [24]

Five

The diagram that represents rays from the sun is given below.

The answer from the diagram is parallel lines.

Six

The formula for this is n_i * Sin(i) = n_r * sin(r)

n1 = 1.333 water

n2 = 1.309 ice

i (angle) = 40o

r (angle) = ?

Solution

1.333 * sin(40) = 1.309*sin(r)

1.333 * sin(40)/1.309 = sin(r)

0.6546 = sin(r)

sin-1(0.6546)  = 40.88 degrees.

I guess my closest answer would be A. I'm not rounding at all and that's the answer I get.

6 0
3 years ago
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