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4 years ago

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A 0.1 m by 0.1 m sheet of cardboard is placed in a uniform electric field of 10 N/C. At first, the plane of the sheet is oriente

d perpendicular to the electric field vector so that the electric flux through the sheet is 0.01 N-m2/C. By what angle do you need to rotate the sheet to reduce the electric flux by 1/2?

1 answer:

Eduardwww [97]4 years ago

4 0

Answer:

The angle is 89°.

Explanation:

Given that,

Electric field = 10 N/C

Electric flux = 0.01 N-m²/C

Area $A=\pi\times(0.1)^2$

We need to calculate the angle

Using formula of electric flux

$\phi=EA\cos\theta$

$\cos\theta=\dfrac{\phi}{EA}$

Where, E = electric field

$\phi$ = electric flux

A = area

Put the value into the formula

$\cos\theta=\dfrac{\dfrac{0.01}{2}}{10\times\pi\times(0.1)^2}$

$\theta=\cos^{-1}(0.01592)$

$\theta=89.0^{\circ}$

Hence, The angle is 89°.

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