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sladkih [1.3K]
3 years ago
5

What is the equation of the line described below written in slope-intercept form? the line passing through point (2, 2) and perp

endicular to the line whose equation is y = x
Mathematics
1 answer:
Julli [10]3 years ago
7 0
To write a slope intercept equation you need the slope and the y intercept which is b. The slope of y=x is 1 and to find a perpendicular slope you flip it and make it the opposite sign so in this case is would still be 1\1 but now it will be negative so your slope is -1 and you plug in 2 for x and 2 for y into the equation y=mx+b and m=your slope (which is -1) to find the value of b. so you get y=-1(2)+b. When you solve you get b=4 and then rewrite the intercept slope equation which is y=mx+b and plug in your slope for m and 4 for b so your final answer is y=-1x+4
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What expression is equivalent to -3+2/3y-4-1/3y
Neko [114]

Answer:

The simplified form of the given expression is -7 + (\frac{1}{3})y

Step-by-step explanation:

Here, the given expression is:

-3 + (\frac{2}{3}) y - 4 - (\frac{1}{3})y

Now to simplify the given expression, perform operations on LIKE TERMS:

We get:

-3 + (\frac{2}{3}) y - 4 - (\frac{1}{3})y  =( -3  - 4)  + [(\frac{2}{3}) y- (\frac{1}{3})y]\\= - 7  + [(\frac{2}{3}) -(\frac{1}{3})]y  = -7 + [\frac{2-1}{3}]y\\ = -7 + (\frac{1}{3})y\\ \implies -3 + (\frac{2}{3}) y - 4 - (\frac{1}{3})y =   -7 + (\frac{1}{3})y

Hence the simplified form of the given expression is -7 + (\frac{1}{3})y

6 0
3 years ago
HELPPPPPPPPPPPPPPPPPPPPPPPP
rodikova [14]
For question 22, divide each number by 1.41 to see which one produces a quotient larger than 0.9. d is the answer.
For #23, multiple 0.155 million by 86%, the result is 133,300
again, d is the correct answer. 
7 0
3 years ago
write a polynomial function of least degree with integral coefficients that has the given zeros. -(1/3), -i
inessss [21]

Answer:

f(x)=3x^3+x^2+3x+1

Step-by-step explanation:

If a real number -\frac{1}{3} is a zero of polynomial function, then

x-\left(-\dfrac{1}{3}\right)=x+\dfrac{1}{3}

is the factor of this function.

If a complex number -i is a xero of the polynomial function, then the complex number i is also a zero of this function and

x-(-i)=x+i\ \text{ and }\ x-i

are two factors of this function.

So, the function of least degree is

f(x)=\left(x+\dfrac{1}{3}\right)(x+i)(x-i)=\left(x+\dfrac{1}{3}\right)(x^2-i^2)=\\ \\ =\left(x+\dfrac{1}{3}\right)(x^2+1)=\dfrac{1}{3}(3x+1)(x^2+1)=\dfrac{1}{3}(3x^3+x^2+3x+1)

If the polynomial function must be with integer coefficients, then it has a form

f(x)=3x^3+x^2+3x+1

4 0
4 years ago
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