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Korolek [52]
3 years ago
12

Using the traditional formula, a 95% CI for p1 − p2 is to be constructed based on equal sample sizes from the two populations. F

or what value n (= m) will the resulting interval have width at most 0.4 irrespective of the results of the sampling? (Round your answer up to the nearest whole number.) n =
Mathematics
1 answer:
inn [45]3 years ago
8 0

Answer:

49

Step-by-step explanation:

Given:

Width = 0.4

Let's take the z value of 95% which is = 1.96

Let's assume population proportion p1 and p2 = 0.5

For margin of error E, the relation between the width and margin of error is 2E.

i.e 2E = 0.4

E = 0.2

To find the sample size, n, let's use the formula :

n= \frac{z^2*(p_1(1-p_1) + p_2(1-p_2))}{E^2}

= \frac{1.96^2(0.5(1-0.5)+0.5(1-0.5))}{0.2^2}

= 48.02

≈ 49

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Answer:

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Step-by-step explanation:

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3 0
2 years ago
Read 2 more answers
Students pass a test it they score 50% or more. the marks of a large number of students were sampled and the mean and standard d
Schach [20]
So we are given that the mean is 42% and the sd (standard deviation) is 8%
Assuming our data is normal we can use the 68-95-99 rule

So one thing you should realize is that 42% + 8% is 50% which is passing. That is one standard deviation higher. So we use:
 
100 - 68 - 13.5 - 2.35 - 0.15  = 16. That means 16% of students passed the test. Which is terrible. They probably need to hit the books more.

Anyways if you have any question feel free to message me!
Hopes this helps!
3 0
3 years ago
Jo says she can find the percent equivalent of 3/4 by multiplying the percent equivalent of 1/4 by 3.how can you use a percent b
WINSTONCH [101]
  The percent equivalent to 1 / 4 = 25 %.
  The percent equivalent to 3 / 4 = 75 %.
   25 %  x  3  = 75 %   ( correct )
5 0
2 years ago
what is this number? 1,010,020,030,040,050,060,070,080,090,010,020,030,040,050,060,070,080,090,010,020,030,040,050,060,070,080,0
Andrei [34K]

Answer:

that isn't a number

Step-by-step explanation:

3 0
1 year ago
The mean time it takes to walk to the bus stop is 8 minutes (with a standard deviation of 2 minutes) and the mean time it takes
11111nata11111 [884]
(a) Average time to get to school
Average time (minutes) = Summation of the two means = mean time to walk to bus stop + mean time for the bust to get to school = 8+20 = 28 minutes

(b) Standard deviation of the whole trip to school
Standard deviation for the whole trip = Sqrt (Summation of variances)

Variance = Standard deviation ^2
Therefore,
Standard deviation for the whole trip = Sqrt (2^2+4^2) = Sqrt (20) = 4.47 minutes

(c) Probability that it will take more than 30 minutes to get to school
P(x>30) = 1-P(x=30)
Z(x=30) = (mean-30)/SD = (28-30)/4.47 ≈ -0.45
Now, P(x=30) = P(Z=-0.45) = 0.3264
Therefore,
P(X>30) = 1-P(X=30) = 1-0.3264 = 0.6736 = 67.36%

With actual average time to walk to the bus stop being 10 minutes;

(d) Average time to get to school
Actual average time to get to school = 10+20 = 30 minutes

(e) Standard deviation to get to school
Actual standard deviation = Previous standard deviation = 4.47 minutes. This is due to the fact that there are no changes with individual standard deviations.

(f) Probability that it will take more than 30 minutes to get to school
Z(x=30) = (mean - 30)/Sd = (30-30)/4.47 = 0/4.47 = 0

From Z table, P(x=30) = 0.5
And therefore, P(x>30) = 1- P(X=30) = 1- P(Z=0.0) = 1-0.5 = 0.5 = 50%
8 0
3 years ago
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