Answer:
i believe the bottom is a <em>irregular quadrilateral </em>and the first one is a <em>parallelogram </em>
Step-by-step explanation:
Answer:
1. 41/45.
2. x/(x^2+3x+6)
Step-by-step explanation:
1.
So first we fill the ven diagram.
There are 240 in band, so we fill that. 60 students are in both, we put that in the middle, and there are 110 people in choir.
now, since we want the probability that a student is chosen that is in band, and choir, and both. We add all this up
240 + 60 + 110 = 410.
The total possible outcome is 410, and the total outcome is 450, so the answer is
410/450 = 41/45
2.
First, to get the total outcomes, we have to add all the expressions together.
x(x-2) + x + 2x+8 = x^2 - 2 + x + 2x + 8 = x^2 - 2 + 3x + 8 = x^2 + 3x + 6.
Since that is the total outcome, we have to find the possible outcomes.
The problem wants BOTH from the 20th century and British, so it is x.
x/(x^2+3x+6). We cannot simplify any further, thus x/(x^2+3x+6) is our answer
Step-by-step explanation:
The amount of time from 10pm to 7am is 9 hours. However, the time indicated is 7:10am. Since there are 60 minutes in an hour, 10 min is equal to 1/6 of an hour. Therefore, the total time that the water level of the pool decreased is 
hours or 
hours. To find the rate at which the water level decreased, we divide the change in the water (in inches) by the time it took to reach that level. So we write
rate of change 
Answer:
A)Yes they should market the wax, because it melts before 55 seconds
C) Null hypothesis: mean <55 vs. Alternative hypothesis :mean =55
D) the value is 51.33 seconds
Step-by-step explanation:
The selected samples for the champion are : 57.9, 62.9, 50.6, 50.5,48.2,47.2,50.2 and 43.1
The mean is ;
Sum =57.9 + 62.9 + 50.6 + 50.5+48.2+47.2+50.2+ 43.1 =410.6
Mean= 410.6/8 =51.33= mean
Assuming Significant =0.05 thus applying this level will give you 51.28-51.38
if specifically, the mean time to finish their standard test course should be less than 55 seconds for a former Olympic champion, then the null hypothesis is correct
Then;
Null hypothesis: mean <55
Alternative hypothesis :mean =55
