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3 years ago

Solve the equation -10x + 1 + 7x = 37

Mathematics

2 answers:

Hatshy [7]3 years ago

6 0

Answer:

$x = -12$

Step-by-step explanation:

Step 1: Combine like terms

$(-10x + 7x) + 1 = 37$

$-3x + 1 = 37$

Step 2: Subtract 1 from both sides

$-3x + 1 - 1 = 37 - 1$

$-3x = 36$

Step 3: Divide both sides by -3

$-3x / -3 = 36 / -3$

$x = -12$

Answer: $x = -12$

kodGreya [7K]3 years ago

4 0

Answer:

x = -12

Step-by-step explanation:

-10x + 1 + 7x = 37

Combine like terms

-3x +1 = 37

Subtract 1 from each side

-3x +1 -1= 37-1

-3x = 36

Divide each side by -3

-3x/-3 = 36/-3

x = -12

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4 years ago

What are the solutions of x² + 6x - 6 = 10?

Likurg_2 [28]

Answer: x=- 8 or x=2

Step-by-step explanation:

1. To solve this problem you can applly the quadratic formula, which is shown below:

$x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}$

2. The quadratic equation is:

$x^{2}+6x-6-10=0\\x^{2}+6x-16=0$

3. Then:

a=1

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c=-16

4. Therefore, when you substitute these values into the quadratic formula, you obtain the following result:

$x=\frac{6+/-\sqrt{6^{2}-4(1)(-16)}}{2(1)}$

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4 0

3 years ago

Read 2 more answers

1: In order to solve the inequality -1/4 x > 8, which of the following steps must be done?

pogonyaev

Answer:

Step-by-step explanation:

-1/4x>8

x>8/(-1/4)

x>(8/1)(-4/1)

x>-32/1

x>-32

x<-32

The answer is D.

--------------------------

-3t+7>=9

-3t>=9-7

-3t>=2

t>=2/-3

t>=-2/3

t<=-2/3

The answer is A.

3 0

3 years ago

Please help me answer thanks.

Dmitry_Shevchenko [17]

Answer:

see explanation

Step-by-step explanation:

Given that M is directly proportional to r³ then the equation relating them is

M = kr³ ← k is the constant of proportion

To find k use the condition when r = 4, M = 160, thus

160 = k × 4³ = 64k ( divide both sides by 64 )

2.5 = k

M = 2.5r³ ← equation of variation

(a)

When r = 2, then

M = 2.5 × 2³ = 2.5 × 8 = 20

(b)

When M = 540, then

540 = 2.5r³ ( divide both sides by 2.5 )_

216 = r³ ( take the cube root of both sides )

r = $\sqrt[3]{216}$ = 6

5 0

4 years ago