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Hatshy [7]
4 years ago
12

Substituents on an aromatic ring can have several effects on electrophilic aromatic substitution reactions. Substituents can act

ivate or deactivate the ring to substitution, donate or withdraw electrons inductively, donate or withdraw electrons through resonance, and direct substitution either to the ortho/para or to the meta positions. From the lists of substituents, select the substituents that correspond to each indicated property. The substituents are written as -XY, where X is the atom directly bound to the aromatic ring.
1. Activation of the ring towards substitution.

a. CFS
b. NO2
c. OCOCH3
d. NH2

2. Withdrawal of electrons through resonance.
a. OH
b. S03H
c. CH3
d. COOH
Chemistry
1 answer:
Gala2k [10]4 years ago
8 0

Answer:

Activation of the ring towards substitution: NH2, OCOCH3

Withdrawal of electrons through resonance. COOH, SO3H

Explanation:

During electrophilic substitution, certain substituents may activate or deactivate the benzene ring.

Substitients that activate or deactivate the benzene ring may do so via resonance or inductive effect.

Groups such as -NH2 and OCOCH3 activate the ring via resonance while groups such as -SO3H and -COOH deactivate the ring via resonance.

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The men's world record for swimming 1500.0 m in a long course pool (as of 2007) is 14 min 34.56 s. At this rate, how many second
vesna_86 [32]

Answer:

It will take 140.76 seconds to swim 0.150 miles.

Explanation:

Distance covered by man by swimming for t time= d

d = 1500.0 miles

t = 14 minutes + 34.56 seconds

1 min = 60 seconds

t = 14 × 60 seconds + 34.56 seconds = 874.56 seconds

Speed of the man while swimming = S = \frac{1500.0 m}{874.56 s}=1.715 m/s

If the man swims 0.150 miles with the same speed ,then the time taken by him be T.

0.150 miles = 0.150 × 1609.34 m = 241.401 m

(1 mile= 1609.34 meters)

S=\frac{Distance}{time}=\frac{241.401 m}{T}

1.715 m/s=\frac{241.401 m}{T}

T = 140.76 seconds

It will take 140.76 seconds to swim 0.150 miles.

6 0
4 years ago
Hydrocyanic acid is a weak acid. Therefore, the salt KCN is
Step2247 [10]
It is basic because of the fact that it has a strong base which is KOH and a weak acid HCN and the strong base causes it to remain more basic.
8 0
3 years ago
Một hỗn hợp X gồm CH3OH; C2H5OH; phenol có khối lượng 28,9 gam phản ứng vừa hết với 100ml dung dịch NaOH 2M. Phần trăm theo khối
inn [45]

Answer: bạn viết phương trình Phenol + NaOH

=> nNaOH = nPhenol = 0,2 mol

m Phenol = 0,2x94 = 18,8 gam

%mPhenol = 18,8/28,9% = 65,05

Explanation:

5 0
3 years ago
Volume of a gas at STP, if its volume is 80.0 mL at 1.08 atm and –12.5oC.
vodomira [7]

Answer:

90.5mL is the volume of the gas at STP

Explanation:

It is possible to find volume of a gas when conditions of temperature and pressure change using combined gas law:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

Where P is pressure, V is volume and T is absolute temperature. 1 is initial conditions and 2 final conditions.

If initial conditions are 1.08atm, 80.0mL and absolute temperature is (-12.5°C + 273.15) = 260.65K.

And STP are 1atm of pressure and 273.15K of absolute temperature. Replacing:

\frac{1.08atm80.0mL}{260.65K} =\frac{1atmV_2}{273.15K}

V₂ = <em>90.5mL is the volume of the gas at STP</em>

7 0
3 years ago
Read 2 more answers
A solution of pH 3 was mixed with a solution of pH 9. What is the final pH could be ?
chubhunter [2.5K]

The solution of which contains of PH 3 called acidic medium which is more stronger acid called HCl when reacts to the stronger base base NaOH forms the acid base reaction .

According to acid base equation you consider ph5 as PH 9 if you understand it then tell me below

3 0
3 years ago
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