Answer:
The answer to your question is 8.75 x 10 ²⁵ atoms of Magnesium
Explanation:
Data
Atomic mass of Magnesium = 24.31 g
Atoms of magnesium = 3.60 x 10²⁴
Process
Solve this porblem using a rule of three
1 atom of Magnesium --------------- 24.31 g
3.60 x 10²⁴ ---------------- x
x = (3.60 x 10²⁴ x 24.31) / 1
x = 8.75 x 10 ²⁵ atoms
Answer: 
Explanation: According to law of conservation of mass, mass can neither be created nor be destroyed.
Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
This is an example of combustion reaction in which hydrocarbon reacts with oxygen to form carbon dioxide and water. This is an exothermic reaction in which a large amount of heat is liberated, thus water also exists as vapors.
Answer:
Explanation:
One CH4 molecules = 10 electrons ( Carbon 6e + 4Hydrogen 4e)
A mole of any substance witll have = 6.023*10^23 atom/ molecuels,
One mole of any substnce is equal is nothing but its moalr mass
Molar mass of CH4 = 16.04
It mean,
16.04 g of CH4 has = 6.023*10^23 molecules of methane
but
4.2 gram of CH4 = 6.023*10^23 * 4.2 /16.04 = 1.58*10^23 molecuels of CH4
So one molecule has =10 electrons
1.58*10^23 molecuels will have = 1.58*10^23 * 10 = 1.58*10^24
Hope this help you
Answer:
0.22 mol HClO, 0.11mol HBr.
0.25mol NH₄Cl, 0.12 mol HCl
Explanation:
A buffer is defined as a mixture in solution between weak acid and its conjugate base or vice versa.
Potassium hypochlorite (KClO) could be seen as conjugate base of HClO (Weak acid). That means the addition of <em>0.22 mol HClO </em>will convert the solution in a buffer. HBr reacts with KClO producing HClO, thus, <em>0.11mol HBr</em> will, also, convert the solution in a buffer. 0.23 mol HBr will react completely with KClO and in the solution you will have only HClO, no a buffering system.
Ammonia (NH₃) is a weak base and its conjugate base is NH₄⁺. That means the addition of <em>0.25mol NH₄Cl</em> will convert the solution in a buffer. Also, NH₃ reacts with HCl producing NH₄⁺. Thus, addition of<em> 0.12 mol HCl</em> will produce NH₄⁺. 0.25mol HCl consume all NH₃.
