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lozanna [386]
3 years ago
5

The discovery of the electron as a subatomic particle was a result of

Chemistry
2 answers:
Nadya [2.5K]3 years ago
8 0

Answer:

J.J Thompson paved the path for experiments with subatomic particles with his discovery of the electron in the early twentieth century.

Explanation:

liberstina [14]3 years ago
5 0

The discovery of the electron as a subatomic particle was a result of English physicist J.J. Thomson

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How many grams of sodium hydroxide, NaOH, are needed to make 355.0 mL of a 4.75M solution? The molar mass of NaOH is 40.00 g/mol
Katen [24]

Answer:

4198.97404999

Explanation:

In chemistry, the formula weight is a quantity computed by multiplying the atomic weight (in atomic mass units) of each element in a chemical formula by the number of atoms of that element present in the formula, then adding all of these products together.

Using the chemical formula of the compound and the periodic table of elements, we can add up the atomic weights and calculate molecular weight of the substance.

If the formula used in calculating molar mass is the molecular formula, the formula weight computed is the molecular weight. The percentage by weight of any atom or group of atoms in a compound can be computed by dividing the total weight of the atom (or group of atoms) in the formula by the formula weight and multiplying by 100.

8 0
2 years ago
A 35.0-g piece of copper wire is heated, and the temperature of the wire changes from 29.0°C to 76.0C. The amount of heat absorb
kotykmax [81]

Answer:

0.15cal/g°C

Explanation:

Given parameters:

Mass of copper piece = 35g

Initial temperature = 29°C

Final temperature  = 76°C

Amount of heat absorbed  = 243cal

Unknown:

Specific heat of copper = ?

Solution:

The specific heat is the amount of heat supplied to a unit mass of substance that causes a 1°C rise in temperature.

   Specific heat C, = \frac{H}{m(T_{2} - T_{1}  )}

where H is the amount of heat supplied

           m is the mass of the copper

           T is the temperature

Input the parameters;

             C = \frac{243}{35(76 - 29)}   = 0.15cal/g°C

       

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