Compounds X has the formula C7H15Cl; Y is C7H15Br. X undergoes base-promoted E2 elimination to give a single alkene product Z. Y
1 answer:
Answer:
See explanation and image attached
Explanation:
Let us examine the statements in the question carefully. First of all, we will discover that the products of the E2 elimination of the both compounds are isomeric. However Y does not undergo SN2 reaction as X does.
The fact that SN2 reaction does not occur in Y confirms that the bromine atom is attached to a tertiary carbon atom and SN2 reaction does not occur due to steric hinderance. Since X undergoes SN2 reaction in aprotic solvent, the chlorine atom must be attached to a secondary carbon atom.
However, E2 reactions does occur with tertiary alkyl halides when strong bases such as OH^- or RO^- are used.
The question also stated that the catalytic hydrogenation of Z affords 3-ethylpentane.
Putting all these together, the structures of X and Y have been suggested in the image attached to this answer.
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