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Lady bird [3.3K]
2 years ago
9

Compounds X has the formula C7H15Cl; Y is C7H15Br. X undergoes base-promoted E2 elimination to give a single alkene product Z. Y

likewise reacts under similar conditions to give a single alkene product that is isomeric with Z Catalytic hydrogenation of Z affords 3-ethylpentane. X readily reacts in SN2 fashion with sodium iodide in acetone. Y does not undergo a similar SN2 reaction. Propose structures for X and Y.
Chemistry
1 answer:
djverab [1.8K]2 years ago
3 0

Answer:

See explanation and image attached

Explanation:

Let us examine the statements in the question carefully. First of all, we will discover that the products of the E2 elimination of the both compounds are isomeric. However Y does not undergo SN2 reaction as  X does.

The fact that SN2 reaction does not occur in Y confirms that the bromine atom is attached to a tertiary carbon atom and SN2 reaction does not occur due to steric hinderance. Since X undergoes SN2 reaction in aprotic solvent, the chlorine atom must be attached to a secondary carbon atom.

However, E2 reactions does occur with tertiary alkyl halides when strong bases such as OH^- or RO^- are used.

The question also stated that the catalytic hydrogenation of Z affords 3-ethylpentane.

Putting all these together, the structures of X and Y have been suggested in the image attached to this answer.

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What would happen to life if earth were in a different location within the solar system
chubhunter [2.5K]
Closer=Burn
Farther=Freeze
We are the perfect distance away from the sun for it to sustain life.
3 0
3 years ago
In which of the following types of solution is the rate of dissociation equal to the rate of crystallization? Concentrated Super
Butoxors [25]

In a <u>Saturated </u>solution, the rate of dissociation equal to the rate of crystallization

Explanation:

A saturated solution is one than cannot dissolve any more solute because the solutes inter-molecular spaces are filled with the solute molecules at that temperature. When an attempt is made to dissolve more solute into the solution, the rate at which the solute is dissolved into the solution is equal to the rate at which excess solute is precipitated and crystallized.

5 0
3 years ago
What salt is produced in each of the following neutralization reactions? HNO3(aq)+KOH(aq)→H2O(l)+? HNO3(aq)+Ca(OH)2(aq)→H2O(l)+?
Igoryamba

Answer:

1. KNO3

2. Ca(NO3)2

3. CaCl2

4. KCl

Explanation:

In each of the neutralization reactions, the H from one of the reactant(acid) will combine with the OH from the other reactant (base) to form water while the other elements combine to give the salt as shown below:

1. HNO3 + KOH → H2O + KNO3

The salt produced is KNO3

2. 2HNO3 + Ca(OH)2 → 2H2O + Ca(NO3)2

The salt produced is Ca(NO3)2

3. 2HCl +Ca(OH)2 → 2H2O + CaCl2

The salt produced is CaCl2

4. HCl +KOH → H2O + KCl

The salt produced is KCl

5 0
2 years ago
Helpppppppp plzzzzzz asaaaapppp
9966 [12]

Answer:

Alright, the first thing we have to do is to balance the chemical equation

2Na3N -----> 6Na + 1N2

We have 60g of Na3N, we convert them into moles by dividing the mass of the compound by the molar mass.

Molar mass of Na3N = (22.98 x 3) + (14) = 82.94g/mol

  <u>60</u>          =  0.72341451651 moles of Na3N

82.94

Now because we did the balanced equation, we know the mole to mole ratio of Na3N to N2 would be 2:1, so in order to get the moles of N2 you have to divide the moles of Na3N by 2

0.72341451651 moles/2 = 0.361707258 moles of N2

Now that we have the moles of N2, we just have to determine the mass of it in grams. In order to do that, just multiply the moles by the molar mass of N2 (28g/mol)

0.361707258 x 28 = <u>10.13g of N2</u>

<u>Therefore the decomposition of 60g of Na3N would result in 10.13g of N2 (nitrogen gas)</u>

3 0
2 years ago
determine whether the nucleus or the electron cloud contributes the most to the volume of an atom. Explain.
Dima020 [189]

Answer:

The electron cloud

Explanation:

<em>Rutherford’s gold foil experiment</em> showed that the atom consisted of a tiny nucleus inside of a much larger electron cloud.

The diameter of the electron cloud is about 50 000 times that of the nucleus.

5 0
3 years ago
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