Answer:
115060 J
Explanation:
From the question given above, the following data were obtained:
Mass (M) = 500 g
Initial temperature (T1) = 20 °C
Final temperature (T2) = 75 °C
Change in temperature (ΔT) = 55 °C
Specific heat capacity (C) = 4.184 J/g°C
Heat (Q) required =?
The heat required to change the temperature of the water can obtained as follow:
Q = MCΔT
Q = 500 × 4.184 × 55
Q = 115060 J
Therefore, the heat needed to change the temperature of the water is 115060 J.
The answer would just be:
<span>Tungsten
</span>hope that this helps you! =)
Answer:
density = 4.763pounds per liter
Explanation:
1g/cm³ = 2.205pounds per liter
2.16g/cm³ = (unknown)pounds per liter
(unknown)pounds per liter = 2.205 x 2.16 = 4.763
density = 4.763pounds per liter
Answer:
1. 
2. 
Explanation:
Hello,
1. In this case, since the volume of the rock is obtained via the difference between the volume of the cylinder with the water and the rock and the volume of the cylinder with the water only:

Thus, the density turns out:

2. In this case, given the density and mass of aluminum we can compute its volume as follows:

Moreover, as the volume is also defined in terms of width, height and length:

The height is computed to be:

Best regards.
Answer:
a) Ka= 7.1 × 10⁻⁴; This is a weak acid because the acid is not completely dissociated in solution.
Explanation:
Step 1: Write the dissociation reaction for nitrous acid
HNO₂(aq) ⇄ H⁺(aq) and NO₂⁻(aq)
Step 2: Calculate the acid dissociation constant
Ka = [H⁺] × [NO₂⁻] / [HNO₂]
Ka = 0.022 × 0.022 / 0.68
Ka = 7.1 × 10⁻⁴
Step 3: Determine the strength of the acid
Since Ka is very small, nitrous acid is a weak acid, not completely dissociated in solution.