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STatiana [176]
4 years ago
9

What is the solution to x = square root 3x + 10?

Mathematics
1 answer:
sdas [7]4 years ago
6 0

Answer:

x = 5

Step-by-step explanation:

Given

x = \sqrt{3x+10} ( square both sides )

x² = 3x + 10 ( subtract 3x + 10 from both sides )

x² - 3x - 10 = 0 ← in standard form

(x - 5)(x + 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 5 = 0 ⇒ x = 5

x + 2 = 0 ⇒ x = - 2

As a check

Substitute these values into the equation and if both sides are equal then they are solutions.

x = 5

right side = \sqrt{15+10} = \sqrt{25} = 5 = left side ← solution

x = - 2

right side = \sqrt{-6+10} = \sqrt{4} = 2 ≠ - 2 ← not a solution

Thus x = 5 is the solution to the equation

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sertanlavr [38]

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Consider the given expression is

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The radical form of given expression.

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(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}

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