Answer:
The slope is Negative three-halves and contains the point (0, 2).
Step-by-step explanation:
(-3,-4)(3,0)
M= -4/-6 = 2/3
⊥M = -3/2
0 = 2/3(3) + B
B=2
Answer:
- square: 9 square units
- triangle: 24 square units
Step-by-step explanation:
Using a suitable formula the area of a polygon can be computed from the coordinates of its vertices. You want the areas of the given square and triangle.
<h3>Square</h3>
The spreadsheet in the first attachment uses a formula for the area based on the given vertices. It computes half the absolute value of the sum of products of the x-coordinate and the difference of y-coordinates of the next and previous points going around the figure.
For this figure, going to that trouble isn't needed, as a graph quickly reveals the figure to be a 3×3 square.
The area of the square is 9 square units.
<h3>Triangle</h3>
The same formula can be applied to the coordinates of the vertices of a triangle. The spreadsheet in the second attachment calculates the area of the 8×6 triangle.
The area of the triangle is 24 square units.
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<em>Additional comment</em>
We have called the triangle an "8×6 triangle." The intention here is to note that it has a base of 8 units and a height of 6 units. Its area is half that of a rectangle with the same dimensions. These dimensions are readily observed in the graph of the vertices.
Answer:
The diagonals bisect each other.
Step-by-step explanation:
Not all diagonals of a parallelogram are equal.
The only quadrilaterals with all four sides being congruent are rhombus and squares so parallelogram is wrong.
The diagonals of a parallelogram bisect each other.
The diagonals of a parallelogram are only perpendicular when it is a square.
The answer to 41 divided by 8,928 would be 0.0046
<h3>
Answer: B) Median</h3>
The middle vertical line inside the box is the median or the value of Q2. The term "median" is used more often instead of Q2, but your book may use this terminology as well.
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side notes:
* The left and right edges of the box are Q1 and Q3 respectively
* The IQR (interquartile range) is found by subtracting Q3 and Q1
* The min and max are the left and right most edges of the the whiskers, this is assuming there are no outliers
* There is no way to get the mean or mode from a box and whisker plot alone.
* The term "average" is too vague and could refer to mean, median, or mode.