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MAVERICK [17]
3 years ago
9

A water tank is 5/8 full. It needs 330 Litres to fill it. What will the tank hold when full? ​

Mathematics
1 answer:
Allisa [31]3 years ago
8 0

Answer:

528 Litres

Step-by-step explanation:

If 5/8 is 330 Litres

you want to work out what 8/8 is

the first step you would take is to find 1/8. you can do this by dividing by 5

therefore 1/8 is 66 Litres (what you do to one side, you must do to the other)

now, you are able to find 8/8. you do this by multiplying both sides by 8

therefore you get 8/8 or 1 whole is 528 Litres

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Find the value of x please and thank you
Pachacha [2.7K]

Given:

In triangle DEF, HG is parallel to DF.

To find:

The value of x.

Solution:

In triangles DEF and GEH,

\angle DE F\cong \angle GEH          (Common angle)

\angle EDF\cong \angle EGH          (Corresponding angle)

\Delta DE F\sim \Delta GEH             (By AA property of similarity)

We know that corresponding sides of similar triangle are proportional.

\dfrac{DE}{GE}=\dfrac{DF}{GH}

\dfrac{9+(x+5)}{x+5}=\dfrac{12}{6}

\dfrac{x+14}{x+5}=2

x+14=2(x+5)

x+14=2x+10

Isolating variable terms, we get

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2 years ago
simplify negative 3 and 1 over 9 − negative 8 and 1 over 3. negative 11 and 1 over 12 negative 5 and 2 over 9 5 and 2 over 9 11
garri49 [273]
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3 years ago
Terri Vogel, an amateur motorcycle racer, averages 129.71 seconds per 2.5 mile lap (in a 7 lap race) with a standard deviation o
Vikki [24]

Answer:

(a) The percent of her laps that are completed in less than 130 seconds is 55%.

(b) The fastest 3% of her laps are under 125.42 seconds.

(c) The middle 80% of her laps are from <u>126.80</u> seconds to <u>132.63</u> seconds.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of seconds for a randomly selected lap.

The random variable <em>X </em>is normally distributed with mean, <em>μ</em> = 129.71 seconds and standard deviation, <em>σ</em> = 2.28 seconds.

Thus, X\sim N(129.71,\ 2.28^{2}).

(a)

Compute the probability that a lap is completes in less than 130 seconds as follows:

P(X

                   =P(Z

The percentage is, 0.55 × 100 = 55%.

Thus, the percent of her laps that are completed in less than 130 seconds is 55%.

(b)

Let <em>x</em> represents the 3rd percentile.

That is, P (X < x) = 0.03.

⇒ P (Z < z) = 0.03

The value of <em>z</em> for the above probability is:

<em>z</em> = -1.88

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\-1.88=\frac{x-129.71}{2.28}\\x=129.71-(1.88\times 2.28)\\x=125.4236\\x\approx 125.42

Thus, the fastest 3% of her laps are under 125.42 seconds.

(c)

Let <em>x</em>₁ and <em>x</em>₂ be the values between which the middle 80% of the distribution lie.

That is,

P(x_{1}

The value of <em>z</em> for the above probability is:

<em>z</em> = 1.28

Compute the values of <em>x</em>₁ and <em>x</em>₂ as follows:

-z=\frac{x_{1}-\mu}{\sigma}\\-1.28=\frac{x_{1}-129.71}{2.28}\\x_{1}=129.71-(1.28\times 2.28)\\x=126.7916\\x\approx 126.80               z=\frac{x_{2}-\mu}{\sigma}\\1.28=\frac{x_{2}-129.71}{2.28}\\x_{2}=129.71+(1.28\times 2.28)\\x=132.6284\\x\approx 132.63

Thus, the middle 80% of her laps are from <u>126.80</u> seconds to <u>132.63</u> seconds.

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