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o-na [289]
3 years ago
10

Nola was selling tickets at the high school dance. At the end of the evening, she picked up the cash box and noticed a dollar ly

ing on the floor next to it. She said, I wonder whether the dollar belongs inside the cash box or not. The price of tickets for the dance was 1 ticket for $5 (for individuals) or 2 tickets for $8 (for couples). She looked inside the cash box and found $200 and ticket stubs for the 47 students in attendance. Does the dollar belong inside the cash box or not? (justify/defend)
Mathematics
1 answer:
Black_prince [1.1K]3 years ago
5 0

Answer:

yes

Step-by-step explanation:

s + 2c = 47

5s+8c = 200

which one checks as in the other solution does not have a solution in non-negative integers. On the other hand, the analogous system

s + 2c = 47

5s+8c = 201

with solution s=13 and c=17. So, as in the other solution, we conclude that the extra dollar belongs in the cash box, with 13 singles and 17 couples attending the dance.

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Find the surface area of the regular pyramid. Write your answer as a decimal.
alexdok [17]

Answer:

Hello! answer: 176.6

Hope this helps!

6 0
3 years ago
A regression analysis between sales (y in $1000) and advertising (x in dollars) resulted in the following equation y = 50,000 +
Vikentia [17]

Answer:

D. increase of $1 in advertising is associated with an increase of $6,000 in sales.

Step-by-step explanation:

Every dollar in advertisting is multiply by 6 in the equation, but every unit in y represent $1000. That means that $1 1n advertisting is multiply by 6 and then by $1000, that is $1 in advertisting = $6000 in sales.

4 0
3 years ago
In a quiz-based program, there are three teams A, B and C. There is a total of five rounds in a game; 20 marks are given for eac
9966 [12]

From the given scenarios, the positions of winning of each team is; Team C came first, Team A came second and Team B came third

<h3>How to find probability of winning?</h3>

From the question, we can derive the following;

Marks gained by team A = 3 × 20 = 60 marks

Marks deducted = 2 × 10 = 20 marks

Hence;

Total marks for Team A = 60 - 20 = 40 marks

Marks gained by team B = 2 × 20 = 40 marks

Marks deducted = 2 × 10 = 20 marks

Hence, total marks of team B = 40 - 20 = 20 marks

Marks gained by team C = 3 × 20 = 60 marks

Marks deducted = 1 × 10 = 10 marks

Hence,  total marks of team C = 60 - 10 = 50 marks

Thus, we can conclude that;

Team C came first, Team A came second and Team B came third

Read more about Probability of winning at; brainly.com/question/24756209

#SPJ1

7 0
2 years ago
Help please if you can
antiseptic1488 [7]
What is the question?

6 0
3 years ago
Simplify. (2/5)^4... words to fill in minimum space
Stella [2.4K]
When you have a power to a fraction, you simply take it by the top and then by the bottm.

So, split it into two: (2)^4 and (5)^4

Solve: (2)^4=16
(5)^4=625

So the fraction is: 16/625

Check to see if it reduces: It doesn't. (Odd and even numbers that have no common multiples).

Therefore, that's the answer.
3 0
3 years ago
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