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laila [671]
3 years ago
7

Tim needs 3 pounds of vegetables for a vegetable soup recipe.

Mathematics
1 answer:
klio [65]3 years ago
8 0

Answer:

25/12 - pounds more vegetables

Step-by-step explanation:

first we need to put these variables into like terms

36/12 - 3

8/12 - 2/3

3/12 - 1/4

add the last two up and subtract from the first and you get how much you need left over

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Answer:

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3 years ago
When using the vertical line test to determine if a graph represents a function, the line can only touch the relation
Mamont248 [21]

Answer: The vertical line test is used to determine if a graph of a relationship is a function or not. if you can draw any vertical line that intersects more than one point on the relationship, then it is not a function.

Hope this helps:)

7 0
3 years ago
10 1/8 +2 1/4<br> Show work please<br> and no links
omeli [17]

Step-by-step explanation:

Please refer to the attachment

4 0
2 years ago
What is the difference between (Picture 1) and (picture 2)? A. 0 B. 2 C. 5 D. 6
Vesnalui [34]

Answer:

The difference between the picture is 0  , option A .

Step-by-step explanation:

Given two figures as :

In figure A

The expression is 1 + 3 n  , where n lies from 0 to 4

So , let f (n) = 1 + 3 n

Or,f ( n ) = 1 + 3 ×0 = 1 + 0 = 1

    f ( 1 ) = 1 + 3 ×1 = 1+ 3 = 4

   f ( 2 ) = 1 + 3 ×2 = 1+ 6 = 7

   f ( 3 ) = 1 + 3 ×3 = 1+ 9 = 10

   f ( 4 ) = 1 + 3 ×4 = 1+ 12 = 13

so, summation of ( 1 + 3 n ) from n = 0 to 4  = 1 + 4 + 7 + 10 + 13 = 35

In figure B

The expression is 3 i - 5  , where i lies from 2 to 6

So , let g (i) = 3 i - 5

Or,g ( 2 ) = 3 ×2 - 5 = 6 - 5 = 1

    g ( 3 ) = 3 ×3 - 5 = 9 - 5 = 4

   g ( 4 ) = 3 ×4 - 5 = 12 - 5 = 7

   f ( 5 ) = 3 ×5 - 5 = 15 - 5 = 10

   f ( 6 ) = 3 ×6 - 5 = 18 - 5 = 13

so, summation of ( 3 i - 5 ) from i = 2 to 6  = 1 + 4 + 7 + 10 + 13 = 35

So, The difference between the summation of functions f(n) - g(i) is

f(n) - g(i) = 35 - 35

I.e  f(n) - g(i) = 0

Hence The difference between the picture is 0  , option A .  Answer

4 0
3 years ago
Please answer the followings: W^mW^n=
Lunna [17]

Step-by-step explanation:

W^m=\underbrace{W\cdot W\cdot W\cdot...\cdot W}_{m}\\\\W^n=\underbrace{W\cdot W\cdot W\cdot...\cdot W}_{n}\\\\W^mW^n=\underbrace{(W\cdot W\cdot W\cdot...\cdot W)}_{m}\underbrace{(W\cdot W\cdot W\cdot...\cdot W)}_{n}\\\\=\underbrace{W\cdot W\cdot W\cdot...\cdot W}_{m+n}=W^{m+n}

5 0
3 years ago
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