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Vinvika [58]
3 years ago
13

The length off a swimming pool cover is (2x+1), the width is (x+8). Find the area of the swimming pool as a polynomial in standa

rd form
Mathematics
1 answer:
Rashid [163]3 years ago
5 0
The area of the pool is equal to the length times the width. Substitute the given values to create a polynomial. Then, either distribute or use a value table to multiply the terms. Then, simplify like terms and place the terms in the order of standard form. (2x^2+17x+8)

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A clothing company has 4 different kinds of sweatshirts. Each year, the company makes 60,000 of each kind of sweatshirt. How man
Anna007 [38]

Answer:

Step-by-step explanation:

Given that,

The company makes 4 different sweat shirts

Each year they make 60,000 of each kind.

So, if they will make 60,000 sweat shirt for each brand and the company design 4 different brand.

So, number of brand is 4

n = 4.

Then,

1 brand = 60,000

Therefore, 4 brand = 60,000 × 4

4brand = 240,000 sweat shirts.

So, in a year the company will make 240,000 sweat shirts.

4 0
3 years ago
How many sides does 52 quadrilateral have?
pickupchik [31]
52 quadrilaterals would have 52 ÷ 4 = a
a = your answer.
My answer is reasonable because if you have 52 sides from quadrilaterals you would need to divide by 4 to get the amount of quadrilaterals you have. Check your work by multiplying 4 x a = __ (The blank should be 52)
5 0
3 years ago
6 m 6 m 19 m Not drawn to scale Find the volume of the triangular prism.
Aloiza [94]
The answer is 3) 324
7 0
3 years ago
6x^2 + 66x + 60 factor completely
kiruha [24]

Hi! Let me help you!

  • Remember, factoring looks like so:
  • ab+ac=a(b+c)
  • So, we need to find the greatest common factor (G.C.F.) of the polynomial.
  • In this case, 6 is the GCF, so we factor it out:
  • 6x²+66x+60
  • Divide 6, 66 and 60 by 6:
  • x²+11x+10

<u>Answer:</u>

x²+11x+10

Hope you find it helpful.

\rm{Stargazing{\bold{WithJoy}

3 0
2 years ago
Plz Helppp meeee assapppp
Gwar [14]

Given:

A right angled triangle.

To find:

The value of x.

Solution:

We have,

Base = x

Hypotenuse = \sqrt{5}

In a right angle triangle,

\cos \theta = \dfrac{Base}{Hypotenuse}

For the given triangle,

\cos 45^\circ= \dfrac{x}{\sqrt{5}}

\dfrac{1}{\sqrt{2}}= \dfrac{x}{\sqrt{5}}

Multiply both sides by \sqrt{5}.

\dfrac{\sqrt{5}}{\sqrt{2}}= x

\dfrac{\sqrt{5}}{\sqrt{2}}\times \dfrac{\sqrt{2}}{\sqrt{2}}= x

\dfrac{\sqrt{10}}{2}= x

Therefore, the required value of x is \dfrac{\sqrt{10}}{2}.

8 0
3 years ago
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