Find the slope and the y-intercept in this equation: 3y+6=-2x

2 answers:

7 0

Hello,

To solve this problem, you should first put in it slope intercept form.

Here are the steps:

3y + 6 = -2x Add 6 to both sides
3y = -2x - 6 Divide both sides by 3
y = (-2/3)x - 2

The you can see that the slope is (-2/3) and the y-intercept is (0, -2).

I hope this helps,
MrEQ

taurus [48]3 years ago

3 0

Slope: - 2/3
y intercept: -2

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9. In a rhombus whose side measures 34 and the smaller angle is 42°. Find the length of the larger diagonal, to the nearest tent

Veseljchak [2.6K]

Answer:

63.5

Step-by-step explanation:

The diagonals of a rhombus bisect opposite angles.

The longer diagonal bisects the 42° angle

The larger angle of the rhombus is 180 - 42 = 138

Let x = the length of the longer diagonal

You know two sides and the included angle of a triangle.

Using the law of cosines we get

$x^{2} = 34^{2} + 34^{2} -2(34)(34) cos 138\\ = 1156 + 1156 - 2312 cos 138\\ = 4030.150837...\\x = \sqrt{4030.150837} = 63.48$ $x^{2} = 34^{2} + 34^{2} -2(34)(34)cos 138\\ = 1156 + 1156 - 2312 cos 138\\ = 4030.1508...\\ x = \sqrt{4030.1508} \\ = 63.48$ x^2 = 34^2 + 34^2 - 2(34)(34) cos 138