Answer:
The probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3) = 0.00621
Step-by-step explanation:
This is a normal distribution problem
The mean of the sample = The population mean
μₓ = μ = 4 ounces
But the standard deviation of the sample is related to the standard deviation of the population through the relation
σₓ = σ/√n
where n = Sample size = 100
σₓ = 1.2/√100
σₓ = 0.12
The probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3)
To do this, we first normalize/standardize the 4.3 ounces
The standardized score for any value is the value minus the mean then divided by the standard deviation.
z = (x - μ)/σ = (4.3 - 4)/0.12 = 2.5
To determine the probability of finding an average in excess of 4.3 ounces of this ingredient from 100 randomly inspected 1-gallon samples of regular unleaded gasoline = P(x > 4.3) = P(z > 2.5)
We'll use data from the normal probability table for these probabilities
P(x > 4.3) = P(z > 2.5) = 1 - P(z ≤ 2.5) = 1 - 0.99379 = 0.00621
That's not a good question at all. It's a lot like asking
"What are the statements for News and President Obama ?"
There are at least a hundred formulas that are useful in trigonometry.
One of the most useful is:
In a right triangle, the square of the length of the hypotenuse
is equal to the sum of the squares of the two short sides.
Pythagoras is the name of the ancient Greek mathematician who
discovered that formula. The formula is so useful that it's known
by his name, in his honor.
There is nothing to answer, the screen is blank. Sorry!
The <em>correct answers</em> are:
a)∠ADB; and c)∠BCA.
Explanation:
The measure of an intercepted arc is twice as much as the measure of its inscribed angle. AB corresponds with both ∠ADB and ∠BCA. Since the arc is 120°, each angle would be half of that, or 60°.
