Answer:
it is a solvable equation
Step-by-step explanation:
(x + 2) -3(x - 4) = 6 and x = 4
if x = 4 then fill in all the x's with 4 so the equation is now:
(4 + 2) -3(4 - 4) = 6
Use PEMDAS
Now the equation is 6 - 3(0) = 6
-3 times 0 is 0 so it's 6-0=6
6 = 6
when you put the 4 in for the x variables and the numbers on both sides of the equal sign are the same it makes the equation true
hope this makes sense and hope it helps :)
Answer:
The value of f(z) is not constant in any neighbourhood of D. The proof is as explained in the explaination.
Step-by-step explanation:
Given
For any given function f(z), it is analytic and not constant throughout a domain D
To Prove
The function f(z) is non-constant constant in the neighbourhood lying in D.
Proof
1-Assume that the value of f(z) is analytic and has a constant throughout some neighbourhood in D which is ω₀
2-Now consider another function F₁(z) where
F₁(z)=f(z)-ω₀
3-As f(z) is analytic throughout D and F₁(z) is a difference of an analytic function and a constant so it is also an analytic function.
4-Assume that the value of F₁(z) is 0 throughout the domain D thus F₁(z)≡0 in domain D.
5-Replacing value of F₁(z) in the above gives:
F₁(z)≡0 in domain D
f(z)-ω₀≡0 in domain D
f(z)≡0+ω₀ in domain D
f(z)≡ω₀ in domain D
So this indicates that the value of f(z) for all values in domain D is a constant ω₀.
This contradicts with the initial given statement, where the value of f(z) is not constant thus the assumption is wrong and the value of f(z) is not constant in any neighbourhood of D.
Range is ] -20 , -10 [
both points are disclude according to the empty circle
10. B
11. D
12. C
13. B
14. B
15. D
Answer:
The Answer is multiple choice and the answer is B. Only B.
Step-by-step explanation:
