All categories

2 years ago

The length of a rectangle is three times its width.

Mathematics

1 answer:

Dovator [93]2 years ago

4 0

Answer:192 in^2

Step-by-step explanation:

The solution is in the attached file

You might be interested in

Type the correct answer in the box

ivolga24 [154]

Answer:

$w=V/(lh)$

Step-by-step explanation:

Let

l------> the length of the base of the prism

w------> the width of the base of the prism

h------> the height of the prism

we know that

The volume of the prism is equal to

$V=lwh$

Solve for w

That means-------> isolate the variable w

Divide both sides by (lh)

$V/(lh)=lwh/(lh)$

Simplify

$w=V/(lh)$

7 0

3 years ago

G.O has 3 orange picks for every 2 green. If there are 25 picks in all, how many picks are orange?

Tomtit [17]

There will be 15 orange pickles and 10 green picks

3 0

3 years ago

Find the value of the variable x (2x+12) and 8x-18

maxonik [38]

Answer: Below

Step-by-step explanation:

Just mutiply x on both sides which gives you 2x^2 + 12x then you mutiply 2x^2 then subtract that number on both sides and it gives you x = something then you distribute it on 8(something) - 18 you subtract

3 0

1 year ago

Read 2 more answers

student expanded an expression, as shown. Is the student's work correct? Explain why or why not. −6 ( 4x − 2 13 ) −6(4x) + 6 ( −

sleet_krkn [62]

Answer:

No, the student's work is not correct.

Step-by-step explanation:

Given : Student expanded an expression, as shown.

$-6(4x-\frac{2}{13} )$

$-6(4x)+6(-\frac{2}{13} )$

$-24x-\frac{12}{13}$

To find : Is the student's work correct?

Solution :

The expansion of student is not correct.

Follow the below steps to get correct solution and student mistake,

Step 1 - Write the expression,

$-6(4x-\frac{2}{13} )$

Step 2 - Apply distributive property, $a(b+c)=ab+ac$

$=(-6)(4x)+(-6)(-\frac{2}{13})$

Step 3 - Solve,

$=-24x+\frac{12}{13}$

The student was mistaken in step 2 in solving the sign.

4 0

2 years ago

Read 2 more answers

Fiona wrote the linear equation y = 2/5 x – 5. When Henry wrote his equation, they discovered that his equation had all the same

Hoochie [10]

we have

$y=\frac{2}{5}x-5$

Let's Isolate the variable y in each of the cases and then compare with Fiona's equation to determine the solution of the problem

case A) $x-\frac{5}{4}y= \frac{25}{4}$

Multiply by $4$ both sides

$4x-5y= 25$

$5y=4x-25$

Divide by $5$ both sides

$y=\frac{4}{5}x-5$

therefore

the case A) is not equal to Fiona's equation

case B) $x-\frac{5}{2}y= \frac{25}{4}$

Multiply by $4$ both sides

$4x-10y= 25$

$10y=4x-25$

Divide by $10$ both sides

$y=\frac{2}{5}x-2.5$

therefore

the case B) is not equal to Fiona's equation

case C) $x-\frac{5}{4}y= \frac{25}{2}$

Multiply by $4$ both sides

$4x-5y= 50$

$5y=4x-50$

Divide by $5$ both sides

$y=\frac{4}{5}x-10$

therefore

the case C) is not equal to Fiona's equation

case D) $x-\frac{5}{2}y= \frac{25}{2}$

Multiply by $2$ both sides

$2x-5y= 25$

$5y=2x-25$

Divide by $5$ both sides

$y=\frac{2}{5}x-5$

therefore

the case D) is equal to Fiona's equation

<u>the answer is</u>

$x-\frac{5}{2}y= \frac{25}{2}$

7 0

2 years ago

Read 2 more answers