All categories

3 years ago

Determine whether the variable is qualitative or quantitative. Explain your reasoning. The price of a new computer.

Mathematics

1 answer:

Levart [38]3 years ago

6 0

Answer:

The price of a new computer is quantitative.

Step-by-step explanation:

A variable can be classified as qualitative or quantitative.

Qualitative:

When the possible values of the variables are labels, for example, good or bad, yes or no,...

Quantitative:

When the possible values of the variables are numbers, for example 1, 2, 1000,....

In this question:

The price of a computer is a numeric value, so it is a quantitative variable.

You might be interested in

How do i use properties of exponents

STatiana [176]

You can use the properties of exponents in three ways: Products of Power and Power to Power

Explanation:

Product of a Power: When you multiply exponentials with the same base, you add their exponents

Power to a Power: When you have a power to a power, you multiply the exponents.
Quotient of Powers: When you divide exponentials with the same base, you subtract the exponents.

3 0

3 years ago

How do you use equivalent rates in the real world?

kotykmax [81]

Cross multiplication
or multiplying by a number which goes in both rates

7 0

4 years ago

Neil is a drummer who purchases his drumsticks online. When practicing with the newest pair, he notices they feel heavier than u

Fynjy0 [20]

Answer:

The probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

Step-by-step explanation:

Given:

Weight of a given sample (x) = 2.33 oz

Mean weight (μ) = 1.75 oz

Standard deviation (σ) = 0.22 oz

The distribution is normal distribution.

So, first, we will find the z-score of the distribution using the formula:

$z=\frac{x-\mu}{\sigma}$

Plug in the values and solve for 'z'. This gives,

$z=\frac{2.33-1.75}{0.22}=2.64$

So, the z-score of the distribution is 2.64.

Now, we need the probability $P(x\geq 2.33 )=P(z\geq 2.64)$ .

From the normal distribution table for z-score equal to 2.64, the value of the probability is 0.9959. This is the area to the left of the curve or less than z-score value.

But, we need area more than the z-score value. So, the area is:

$P(z\geq 2.64)=1-0.9959=0.0041=0.41\%$

Therefore, the probability of the stick's weight being 2.33 oz or greater is 0.0041 or 0.41%.

5 0

3 years ago

Edith is x years old. Her sister,Madison is six years older than her. Their mother is twice as old as Madison. Their aunt, Eliza

DENIUS [597]

Answer:

Step-by-step explanation:

Edith is x years old.

Her sister,Madison is six years older than her. This means that the age of Madison is x + 6

Their mother is twice as old as Madison. This means that the age of their mother is expressed as

2(x + 6)

= 2x + 12

Their aunt, Elizabeth is x years older than their mother. This means that the expression that represents Elizabeth's age in years is

2x + 12 + x

= 3x + 12

5 0

3 years ago

How do you do this question?

Ksivusya [100]

Answer:

V = (About) 22.2, Graph = First graph/Graph in the attachment

Step-by-step explanation:

Remember that in all these cases, we have a specified method to use, the washer method, disk method, and the cylindrical shell method. Keep in mind that the washer and disk method are one in the same, but I feel that the disk method is better as it avoids splitting the integral into two, and rewriting the curves. Here we will go with the disk method.

$\mathrm{V\:=\:\pi \int _a^b\left(r\right)^2dy\:},\\\mathrm{V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy}$

The plus 1 in '1 + 2/x' is shifting this graph up from where it is rotating, but the negative 1 is subtracting the area between the y-axis and the shaded region, so that when it's flipped around, it becomes a washer.

$V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=\pi \cdot \int _1^3\left(1+\frac{2}{y}\right)^2-1dy\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\= \pi \left(\int _1^3\left(1+\frac{2}{y}\right)^2dy-\int _1^31dy\right)\\\\$

$\int _1^3\left(1+\frac{2}{y}\right)^2dy=4\ln \left(3\right)+\frac{14}{3}, \int _1^31dy=2\\\\=> \pi \left(4\ln \left(3\right)+\frac{14}{3}-2\right)\\=> \pi \left(4\ln \left(3\right)+\frac{8}{3}\right)$

Our exact solution will be V = π(4In(3) + 8/3). In decimal form it will be about 22.2 however. Try both solution if you like, but it would be better to use 22.2. Your graph will just be a plot under the curve y = 2/x, the first graph.

5 0

3 years ago