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Mnenie [13.5K]
3 years ago
5

When a figure is rotated 360°, it completes one full _____

Mathematics
2 answers:
Aleks [24]3 years ago
6 0

revolution is the answer on Edgeunity

lubasha [3.4K]3 years ago
3 0
Full rotation or full turn
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Is 9/3 a whole number
Liono4ka [1.6K]

Yes! 3x3= 9. Therefore, 3 goes into nine 3 times. So the whole number would be 3.

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3 years ago
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Solve the simultaneous equations:<br> 3x + 2y = 35 <br> 2x + 3y = 30
lesya [120]

Answer:

nuber 1

Simplifying

3x + 2y = 35

Solving

3x + 2y = 35

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2y' to each side of the equation.

3x + 2y + -2y = 35 + -2y

Combine like terms: 2y + -2y = 0

3x + 0 = 35 + -2y

3x = 35 + -2y

Divide each side by '3'.

x = 11.66666667 + -0.6666666667y

Simplifying

x = 11.66666667 + -0.6666666667y

5 0
2 years ago
NEED HELP FAST BRIANLEST
AVprozaik [17]

Answer:

\frac{1}{4}^{2}

Step-by-step explanation:

When you solve these two equations, you end up with the same answer of 1/16 or 0.0625

3 0
2 years ago
2/5g = 3/5<br><br> What does is solve to? <br> Give me a brief explanation please
swat32

Answer:

The answer is 1 and 1/2 or 1.5.

Step-by-step explanation:

I did 3/5 ÷ 2/5. Then I got 3/2. Then I turned the improper fraction into a mixed number.

8 0
3 years ago
Show both decimal places (5.06).
lilavasa [31]

a. the cost of a call for six minutes is 0.70.

b.the cost of a 14-minute call is 2.62.

c.the cost of a 9 ½2-minute call is 1.66.

<h3>How to find the cost of each call ?</h3>

given that

rate schedule for an m-minute call from any of its pay phones 0.70.

c(m) = 0.70 when m<=6

c(m) = 0.70+ 0.24(m-6) when m>6 & m is an integer

c(m) = 0.70+0.24((m-6)+1) when m>6 & m is not an integer.

a. to find the cost of a call for six minutes.

already given that c(m) =0.70 when m=6.

Therefore, the cost of a call for six minutes is 0.70.

b. to find the cost of a 14-minute call.

according to given information

c(14) = 0.70 + 0.24(m - 6) \\ c(14) = 0.70 + 0.24(14 \: - 6)  \\c(14) = 0.70 + (0.24 \times 14) - (0.24 \times 6) \\c(14) = 0.70 + (3.36 - 1.44) \\ c(14) = 0.70 + 1.92 \\ c(14) = 2.62

Therefore,the cost of a 14-minute call is 2.62.

c.to find the cost of a 9 ½2-minute call

according to given information

c(9  \frac{1}{2} 2) = 0.70 + 0.24((9 \frac{1}{2} 2 - 6) + 1) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.24((9 - 6) + 1) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.24(3+ 1) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.24(4) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.96 \\ c(9  \frac{1}{2} 2) = 1.66

Therefore,the cost of a 9 ½2-minute call is 1.66.

Learn more about problems on cost of call, refer:

brainly.com/question/16584226

#SPJ9

4 0
1 year ago
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