Pls someone help me these's problem's!

Mathematics

1 answer:

Iteru [2.4K]2 years ago

3 0

Answer:

15. a because b is being squared by a variable meaning it is exponential and goes forever, but the answer choice B is set only to 3 squared, so a is the answer.

16. D because square root of 96 MINUS square root of 54 on calculator is 2.44948974278, BUT the square root of 6 is ALSO 2.44948974278, so the answer is D or square root of 6

Step-by-step explanation:

my explanation is all on the top

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Simplify x+2x –8+3x+1 –2x.

emmainna [20.7K]

Answer:

4x - 7

Step-by-step explanation:

x + 2x + 3x - 2x = 4x

-8 + 1 = -7

8 0

2 years ago

Suppose z equals f (x comma y ), where x (u comma v )space equals space 2 u plus space v squared, y (u comma v )space equals spa

barxatty [35]

$z=f(x(u,v),y(u,v)),\begin{cases}x(u,v)=2u+v^2\\y(u,v)=3u-v\end{cases}$

We're given that $f_x(6,1)=3$ and $f_y(6,1)=-1$ , and want to find $\frac{\partial z}{\partial v}(1,2)$ .

By the chain rule, we have

$\dfrac{\partial z}{\partial v}=\dfrac{\partial z}{\partial x}\dfrac{\partial x}{\partial v}+\dfrac{\partial z}{\partial y}\dfrac{\partial y}{\partial v}$

and

$\dfrac{\partial x}{\partial v}=2v$

$\dfrac{\partial y}{\partial v}=-1$

Then

$\dfrac{\partial z}{\partial v}(1,2)=\dfrac{\partial z}{\partial x}(6,1)\dfrac{\partial x}{\partial v}(1,2)+\dfrac{\partial z}{\partial y}(6,1)\dfrac{\partial y}{\partial v}(1,2)$