x=71
-46+x=25
add 46 to both sides (you do the inverse!)
x=71
<span><span>(<span><span>5x</span>+7</span>)</span><span>(<span>1/5</span>)</span></span>=<span><span>(<span>8−<span>6x</span></span>)</span><span>(<span>1/5</span><span>)
</span></span></span>Simplify both sides. In order to do this you need to distribute 1/5 in each expression.
<span><span><span>(<span>5x</span>)</span><span>(<span>1/5</span>)</span></span>+<span><span>(7)</span><span>(<span>1/5</span>)</span></span></span>=<span><span><span>(8)</span><span>(<span>1/5</span>)</span></span>+<span><span>(<span>−<span>6x</span></span>)</span><span>(<span>1/5</span><span>)
</span></span></span></span><span>x+<span>7/5</span></span>=<span><span>8/5</span>+<span><span><span>−6/</span>5</span><span>x
</span></span></span><span>x+<span>7/5</span></span>=<span><span><span><span>−6/</span>5</span>x</span>+<span>8/<span>5
Now you need to add (-6/5)x to both sides. This leaves you with
</span></span></span><span><span><span>(5/11)</span>x</span>+<span>7/5</span></span>=<span>8/<span>5
Now subtract 7/5 from both sides.
</span></span><span><span>(5/11)</span>x</span>=<span>1/<span>5
Divide both sides by 5/11
x=1/11</span></span>
Answer:
The proportion of temperatures that lie within the given limits are 10.24%
Step-by-step explanation:
Solution:-
- Let X be a random variable that denotes the average city temperatures in the month of August.
- The random variable X is normally distributed with parameters:
mean ( u ) = 21.25
standard deviation ( σ ) = 2
- Express the distribution of X:
X ~ Norm ( u , σ^2 )
X ~ Norm ( 21.25 , 2^2 )
- We are to evaluate the proportion of set of temperatures in the month of august that lies between 23.71 degrees Celsius and 26.17 degrees Celsius :
P ( 23.71 < X < 26.17 )
- We will standardize our limits i.e compute the Z-score values:
P ( (x1 - u) / σ < Z < (x2 - u) / σ )
P ( (23.71 - 21.25) / 2 < Z < (26.17 - 21.25) / 2 )
P ( 1.23 < Z < 2.46 ).
- Now use the standard normal distribution tables:
P ( 1.23 < Z < 2.46 ) = 0.1024
- The proportion of temperatures that lie within the given limits are 10.24%
Answer:
in 3 minutes and 50 seconds
Step-by-step explanation:
soup = 95c
after 1 minute = 83c
after 2 minutes = 71c
after 3 minutes = 59
soup cools down 0.2c in 1 seconds
so 10 seconds = 2c
in 3 minutes and 50 seconds = 49c