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3 years ago

15

HELP PLZ!

2 answers:

Kay [80]3 years ago

8 0

Answer:

3rd

Step-by-step explanation:

Negative suggests that whatver the graph is, it's the opposite of the original function. That leaves us with 2 and 3 (since 1st one is positive x^3 )

Now, the degree 3 tells you that it has to be number3 because that's the 3rd degree graph, Since second one is a upside down parabola which means -x^2

Hope this cleared things up for you!

labwork [276]3 years ago

5 0

Answer:

$\displaystyle Third\:graph$

Step-by-step explanation:

All you have to do is pick the graph that comes down from the left to the right because the <em>cubic function</em> is negative. This would be a the third graph.

I am joyous to assist you anytime.

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Nana76 [90]

Answer: $k=18\dfrac{8}{11}$ .

Step-by-step explanation:

If a line passing through two points, then

$Slope=\dfrac{y_2-y_1}{x_2-x_1}$

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Slope of MN $=\dfrac{1-0}{5-0}=\dfrac{1}{5}$

The endpoints of segment AB have coordinates $\left(1\dfrac{1}{22} , 2\dfrac{1}{4}\right)$ and $\left(-2\dfrac{1}{4} , k\right)$ .

$A=\left(1\dfrac{1}{22} , 2\dfrac{1}{4}\right)=\left(\dfrac{23}{22} ,\dfrac{9}{4}\right)$

$B=\left(-2\dfrac{1}{4} , k\right)=\left(-\dfrac{9}{4} , k\right)$ .

Slope of AB $=\dfrac{k-\frac{9}{4}}{-\frac{9}{4}-\dfrac{23}{22}}$

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$=\dfrac{4k-9}{4}\times \dfrac{44}{-145}$

$=4k-9\times \dfrac{11}{-145}$

$=\dfrac{44k-99}{-145}$

Product of slopes of two perpendicular segments is -1.

Slope of MN × Slope of AB = -1

$\dfrac{1}{5}\times \dfrac{44k-99}{-145}=-1$

$\dfrac{44k-99}{-725}=-1$

$44k-99=725$

$44k=725+99$

$k=\dfrac{824}{44}$

$k=\dfrac{206}{11}$

$k=18\dfrac{8}{11}$

Therefore, the value of k is $k=18\dfrac{8}{11}$ .

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Step-by-step explanation:

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