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Alenkasestr [34]
3 years ago
15

The parking lot at a store has a width of 20 yards 2 feet and a length of 30 yards

Mathematics
2 answers:
Archy [21]3 years ago
8 0

Answer:

what??

Step-by-step explanation:

Liula [17]3 years ago
5 0

Answer:

I guess you are trying to find the perimeter of the parking lot.

the fomula is P= 2L+2W.

Step by step:

20yards( 2 ft )+ 30 yards +20 yards + 30 yards=

100 yards 2 ft.

I hope it's help.

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Answer:



Step-by-step explanation:

Step 1 Answer: Yes, 3

Step 2 Answer: Yes, 5

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8 0
2 years ago
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Find the value of the variable.
nalin [4]

Answer:

The variable, y is 11°

Step-by-step explanation:

The given parameters are;

in triangle ΔABC;          {}              in triangle ΔFGH;

Segment \overline {AB} = 14         {}               Segment \overline {FG} = 14

Segment \overline {BC} = 27         {}              Segment \overline {GH} = 19

Segment \overline {AC} = 19         {}               Segment \overline {FH} = 2·y + 5

∡A = 32°                       {}                ∡G = 32°

∡A = ∠BAC which is the angle formed by segments \overline {AB} = 14 and \overline {AC} = 19

Therefore, segment \overline {BC} = 27, is the segment opposite to ∡A = 32°

Similarly, ∡G = ∠FGH which is the angle formed by segments \overline {FG} = 14 and \overline {GH} = 19

Therefore, segment \overline {FH} = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;

\overline {FH} ≅ \overline {BC} by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∴ \overline {FH} = \overline {BC} = 27° y definition of congruency

\overline {FH} = 2·y + 5 = 27° by transitive property

∴ 2·y + 5 = 27°

2·y = 27° - 5° = 22°

y = 22°/2 = 11°

The variable, y = 11°

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2 years ago
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4 0
3 years ago
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For example #1 what is the solution
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Answer: what is example 1

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