2/3y-2/5=5
We move all terms to the left:
2/3y-2/5-(5)=0
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
determiningTheFunctionDomain
2/3y-5-2/5=0
We calculate fractions
There is no solution for this equation
Left side: (equation) 2/x=3/90 (multiply them together by cross multiplying. 90x2 divided by 3)
=60
Altogether: 90 (right) + 60 (left) =150 seats in total
A function

is periodic if there is some constant

such that

for all

in the domain of

. Then

is the "period" of

.
Example:
If

, then we have

, and so

is periodic with period

.
It gets a bit more complicated for a function like yours. We're looking for

such that

Expanding on the left, you have

and

It follows that the following must be satisfied:

The first two equations are satisfied whenever

, or more generally, when

and

(i.e. any multiple of 4).
The second two are satisfied whenever

, and more generally when

with

(any multiple of 10/7).
It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when

is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.
Let's verify:


More generally, it can be shown that

is periodic with period

.
Answer:
None of the above
Step-by-step explanation:
Answer:
number 4. 13
because first you do the exponents giving you 8 and then divide which is 2 then you subtract which is 13