To solve for x, you need to isolate/get the variable "x" by itself in the equation:
3x - 3(x + 1) = 3 Distribute/multiply -3 into (x + 1)
3x + (-3)x + (-3)1 = 3
3x - 3x + 1 = 3
1 = 3
Your answer is no solution because the variable "x" is canceled out and 1 ≠ 3
Answer:
Option D. y = 5x + 1
Step-by-step explanation:
From the question given above, the following data were:
Input (x) >>>>>> Output (y)
0 >>>>>>>>>>>> 1
1 >>>>>>>>>>>> 6
2 >>>>>>>>>>>> 11
3 >>>>>>>>>>>> 16
4 >>>>>>>>>>>> 21
To know the the correct answer to the question, we shall apply the equation given in each option to see which will satisfy the table. This can be obtained as follow:
For Option a
y = 3x + 3
x = 0
y = 3(0) + 3
y = 0 + 3
y = 0
y = 3x + 3
x = 1
y = 3(1) + 3
y = 3 + 3
y = 6
For Option b
y = 5x – 4
x = 0
y = 5(0) – 4
y = 0 – 4
y = – 4
y = 5x – 4
x = 1
y = 5(1) – 4
y = 5 – 4
y = 1
For Option c
y = 10x – 9
x = 0
y = 10(0) – 9
y = 0 – 9
y = – 9
y = 10x – 9
x = 1
y = 10(1) – 9
y = 10 – 9
y = 1
For Option d
y = 5x + 1
x = 0
y = 5(0) + 1
y = 0 + 1
y = 1
y = 5x + 1
x = 1
y = 5(1) + 1
y = 5 + 1
y = 6
From the illustrations made above, only option d satisfy the table. Thus, option d gives the correct answer to the question.
Answer:
16.7
Step-by-step explanation:
We can use the Pythagorean theorem, a^2 + b^2 = c^2.
a = 11
c = 20
11^2 + b^2 = 20^2
121 + b^2 = 400
b^2 = 279
b = sqrt(279) = 16.7
Answer:
The two roots of the quadratic equation are
Step-by-step explanation:
Original quadratic equation is 
Divide both sides by 9:
Add 
to both sides to get rid of the constant on the LHS
==> 
Add 
to both sides
This simplifies to
Noting that (a + b)² = a² + 2ab + b²
If we set a = x and b = 
we can see that
= 
So
Taking square roots on both sides
So the two roots or solutions of the equation are
and 
So the two roots are
and
The answer of your problem is C. Because 25 and 100 are related integers.
