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Sindrei [870]
3 years ago
5

Patty's Pet Company charges $0.55 per pound to ship pet supplies.

Mathematics
2 answers:
faust18 [17]3 years ago
5 0
Part A: c = 0.55 × p
c = 0.55 × 2 = $1.1
Part B: c = (0.55 × p) - (0.05 × p)
Alex787 [66]3 years ago
4 0

Answer:

part A $1.10

part B $1.00

Step-by-step explanation:

c = 0.55p when p = 2 you should get a total cost of 1.10 $

since the original price of shipping one pound of pet supplies was 0.55 than you subtract 0.05 to get 0.50 then you multiply 0.50p to get a final cost of 1.00 for shipping

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Match the equation with its corresponding solution for x.
Fudgin [204]

To solve for x, you need to isolate/get the variable "x" by itself in the equation:

3x - 3(x + 1) = 3     Distribute/multiply -3 into (x + 1)

3x + (-3)x + (-3)1 = 3

3x - 3x + 1 = 3

1 = 3

Your answer is no solution because the variable "x" is canceled out and 1 ≠ 3

4 0
3 years ago
Indicate the answer choice that best completes the statement or answers
zysi [14]

Answer:

Option D. y = 5x + 1

Step-by-step explanation:

From the question given above, the following data were:

Input (x) >>>>>> Output (y)

0 >>>>>>>>>>>> 1

1 >>>>>>>>>>>> 6

2 >>>>>>>>>>>> 11

3 >>>>>>>>>>>> 16

4 >>>>>>>>>>>> 21

To know the the correct answer to the question, we shall apply the equation given in each option to see which will satisfy the table. This can be obtained as follow:

For Option a

y = 3x + 3

x = 0

y = 3(0) + 3

y = 0 + 3

y = 0

y = 3x + 3

x = 1

y = 3(1) + 3

y = 3 + 3

y = 6

For Option b

y = 5x – 4

x = 0

y = 5(0) – 4

y = 0 – 4

y = – 4

y = 5x – 4

x = 1

y = 5(1) – 4

y = 5 – 4

y = 1

For Option c

y = 10x – 9

x = 0

y = 10(0) – 9

y = 0 – 9

y = – 9

y = 10x – 9

x = 1

y = 10(1) – 9

y = 10 – 9

y = 1

For Option d

y = 5x + 1

x = 0

y = 5(0) + 1

y = 0 + 1

y = 1

y = 5x + 1

x = 1

y = 5(1) + 1

y = 5 + 1

y = 6

From the illustrations made above, only option d satisfy the table. Thus, option d gives the correct answer to the question.

5 0
3 years ago
Please help me thanks
BabaBlast [244]

Answer:

16.7

Step-by-step explanation:

We can use the Pythagorean theorem, a^2 + b^2 = c^2.

a = 11

c = 20

11^2 + b^2 = 20^2

121 + b^2 = 400

b^2 = 279

b = sqrt(279) = 16.7

5 0
3 years ago
Solve the following equation by factoring:9x^2-3x-2=0
olya-2409 [2.1K]

Answer:

The two roots of the quadratic equation are

x_1= - \frac{1}{3} \text{ and } x_2= \frac{2}{3}

Step-by-step explanation:

Original quadratic equation is 9x^{2}-3x-2=0

Divide both sides by 9:

x^{2} - \frac{x}{3} - \frac{2}{9}=0

Add \frac{2}{9} to both sides to get rid of the constant on the LHS

x^{2} - \frac{x}{3} - \frac{2}{9}+\frac{2}{9}=\frac{2}{9}  ==> x^{2} - \frac{x}{3}=\frac{2}{9}

Add \frac{1}{36}  to both sides

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This simplifies to

x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{1}{4}

Noting that (a + b)² = a² + 2ab + b²

If we set a = x and b = \frac{1}{6}\right) we can see that

\left(x - \frac{1}{6}\right)^2 = x^2 - 2.x. (-\frac{1}{6}) + \frac{1}{36} = x^{2} - \frac{x}{3}+\frac{1}{36}

So

\left(x - \frac{1}{6}\right)^2=\frac{1}{4}

Taking square roots on both sides

\left(x - \frac{1}{6}\right)^2= \pm\frac{1}{4}

So the two roots or solutions of the equation are

x - \frac{1}{6}=-\sqrt{\frac{1}{4}}  and x - \frac{1}{6}=\sqrt{\frac{1}{4}}

\sqrt{\frac{1}{4}} = \frac{1}{2}

So the two roots are

x_1=\frac{1}{6} - \frac{1}{2} = -\frac{1}{3}

and

x_2=\frac{1}{6} + \frac{1}{2} = \frac{2}{3}

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siniylev [52]
The answer of your problem is C. Because 25 and 100 are related integers.
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3 years ago
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