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3 years ago

4(x-2)=2(x+7) helpp pleasee

Mathematics

2 answers:

Talja [164]3 years ago

7 0

4x-8=2x+14

subtract 2x on both sides and add 8 on both sides so x=11

Sergeeva-Olga [200]3 years ago

6 0

Answer:

x = 11

Explanation:

4(x − 2) = 2(x + 7)

Step 1: Simplify both sides of the equation

4(x − 2) = 2(x + 7)

(4)(x) + (4)(−2) = (2)(x) + (2)(7) (Distribute)

4x + −8 = 2x + 14

4x − 8 = 2x + 14

Step 2: Subtract 2x from both sides

4x − 8 − 2x = 2x + 14 − 2x

2x − 8 = 14

Step 3: Add 8 to both sides

2x − 8 + 8 = 14 + 8

2x = 22

Step 4: Divide both sides by 2

2x / 2 = 22 / 2

x = 11

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anyanavicka [17]

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Check the explanation

Step-by-step explanation:

Given the function

$f(x) = \sqrt{x}$

As the function is translated according to the rule

(x, y) → (x - 6, y + 9)

Translation of the function $f(x) = \sqrt{x}$ 6 units to the left will bring the function

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Translation of the function $g(x) = \sqrt{x+6}$ 9 units up will bring the function

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Determining the range of $A\left(x\right)=\sqrt{x+6}+9$

As we know that the range is the set of dependent values for which the function is defined.

$\mathrm{The\:range\:of\:an\:radical\:function\:of\:the\:form}\:c\sqrt{ax+b}+k\:\mathrm{is}\:\:f\left(x\right)\ge \:k$

$k=9$

$f\left(x\right)\ge \:9$

$\mathrm{Range\:of\:}\sqrt{x+6}+9:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:9\:\\ \:\mathrm{Interval\:Notation:}&\:[9,\:\infty \:)\end{bmatrix}$

Therefore, the expression describes the range of A(x) will be:

$f\left(x\right)\ge \:\:9\:or\:y\:\ge \:\:\:9$

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