Answer:
C) x^2 + y^2 = 16
Step-by-step explanation:
<h2><u>Find the equation </u></h2>
since the radius is 4 this means that anywhere from the center of the circle to the edge of the circle is 4. hence :
place the horizontal line of the radius where y = 0 .
this means that if y = 0 , then x = 4
therefore :
x^2 + y^2
4^2 + 0^2
= 16
<h3><u>hence the answer is C ) x^2 + y^2 = 16</u></h3>
<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
Answer: 6a 2(a+2a) and the last one
Step-by-step explanation:
Answer:
fx+gx=5x-11
fx-gx=x-3
Step-by-step explanation:
Answer:
c. $10.56
Step-by-step explanation:
$3.30 x 4 = $13.20 x 0.20 (20%) = $2.64
$13.20 - $2.64 = $10.56
