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2 years ago

A regular polygon has 15 sides. Which is a possible angle of rotational symmetry for the figure? 12° 45° 72° 90°

Mathematics

1 answer:

Agata [3.3K]2 years ago

7 0

Answer:

12 degrees is the correct answer.

Step-by-step explanation:

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Joni has a box that has a mass of 67 dekagrams. She converts this to centigrams. Her work is shown below. 67 dekagrams over 1,00

hichkok12 [17]

Answer: I think it’s B

Step-by-step explanation:

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3 years ago

How many and what type of solution(s) does the equation have?

zzz [600]

Answer:

2 irrational solutions.

Step-by-step explanation:

6p^2 = 8p + 3

0 = -6p^2 + 8p + 3

The roots are:

p = (2/3) - (8.5)^(1/2)/3, and

p = (2/3) + (8.5)^(1/2)/3

These are irrational numbers.

There are 2 irrational solutions.

3 0

2 years ago

The table shows the outputs, y, for different inputs, x:

ASHA 777 [7]

Part A:
Yes, the data represent a function because there is at least one x-value for every y-value.

Part B:
When x=6 in the input-output table, y=14. When x=6 in the relation f(x)=7x-15, f(x)=7(6)-15=27. <span>The equation has a greater value when x=6.

Part C:</span>
Set f(x) equal to 6 in the equation:
6=7x-15
Solve for x:
7x=21
x=3
<span>x=3 when f(x)=6</span>

3 0

3 years ago

A furniture store had a chair that cost $33. After a few months the owner owner took 9% off the price. How much is the chair now

yawa3891 [41]

Answer:

$30.03

Step-by-step explanation:

To find what 9% of 33 is we need to divide 9% by 1

9% ÷ 1 = 2.97

33 - 2.97 = 30.03

4 0

2 years ago

Read 2 more answers

Write an expression for the 12th partial sum of the series 3/2+7/3+19/6+... using summation notation

lapo4ka [179]

Answer:

$S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]$

$S_{12}=73$

Step-by-step explanation:

$First\ term\ of\ the\ series(a_1)=\frac{3}{2}\\\\Second\ term\ of\ the\ series(a_2)=\frac{7}{3}\\\\Third\ term\ of\ the\ series(a_3)=\frac{19}{6}\\\\a_2-a_1=\frac{7}{3}-\frac{3}{2}=\frac{5}{6}\\\\a_3-a_2=\frac{19}{6}-\frac{7}{3}=\frac{5}{6}\\\\Hence\ it\ is\ an\ Arithmetic\ Series\ with\ first\ term=\frac{3}{2}\ and\ constant\ difference=\frac{5}{6}$

$a_1=\frac{3}{2}+0\times \frac{5}{6}\\\\a_2=\frac{3}{2}+1\times \frac{5}{6}\\\\a_3=\frac{3}{2}+2\times \frac{5}{6}\\\\.\\.\\.\\a_n=\frac{3}{2}+(n-1)\times \frac{5}{6}\\\\S_n=a_1+a_2+a_3+......+a_n\\\\S_n=(\frac{3}{2}+0\times \frac{5}{6})+(\frac{3}{2}+1\times \frac{5}{6})+(\frac{3}{2}+2\times \frac{5}{6})+....+(\frac{3}{2}+[n-1]\times \frac{5}{6})\\\\S_n=\sum_{i=1}^n [\frac{3}{2}+(i-1)\times \frac{5}{6}]\\\\S_n=(\frac{3}{2}+\frac{3}{2}+\frac{3}{2}+...n\ times)+\frac{5}{6}(1+2+3+4+...+(n-1))\\\\$

$S_n=\frac{3}{2}\times n+\frac{5}{6}\times \frac{n(n-1)}{2}\\\\$

$S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]$

$S_{12}=\frac{3}{2}\times 12+\frac{5}{6}\times \frac{(12)(12-1)}{2}\\\\S_{12}=18+55\\\\S_{12}=73$

5 0

3 years ago