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mihalych1998 [28]
3 years ago
11

HOW MANT FEET ARE IN 5 YARDS

Mathematics
2 answers:
tester [92]3 years ago
6 0

Answer:

15 feet

Step-by-step explanation:

There are three feet in a yard so three times five is fifteen. So there are fifteen feet in five yards.

ludmilkaskok [199]3 years ago
4 0

Answer:

15 feet

Step-by-step explanation:

a yard is equal to three feet

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Naily [24]

we know that

1\ ten=10

so

by proportion

Find the value of 44\ tens

\frac{1}{10} =\frac{44}{x} \\ \\x=10*44 \\\\x=440

therefore

<u>the answer is</u>

440

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Find all solutions to the equation
tresset_1 [31]

Answer:

0,1,2,3,4,5,6.......19,20

Step-by-step explanation:

in this interval 0 is included and 21 is not included. So starting from 0 up to 20, all are the solutions

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Find dy/dx by implicit differentiation for ysin(y) = xcos(x)
tatyana61 [14]

Answer:

\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}

Step-by-step explanation:

So we have:

y\sin(y)=x\cos(x)

And we want to find dy/dx.

So, let's take the derivative of both sides with respect to x:

\frac{d}{dx}[y\sin(y)]=\frac{d}{dx}[x\cos(x)]

Let's do each side individually.

Left Side:

We have:

\frac{d}{dx}[y\sin(y)]

We can use the product rule:

(uv)'=u'v+uv'

So, our derivative is:

=\frac{d}{dx}[y]\sin(y)+y\frac{d}{dx}[\sin(y)]

We must implicitly differentiate for y. This gives us:

=\frac{dy}{dx}\sin(y)+y\frac{d}{dx}[\sin(y)]

For the sin(y), we need to use the chain rule:

u(v(x))'=u'(v(x))\cdot v'(x)

Our u(x) is sin(x) and our v(x) is y. So, u'(x) is cos(x) and v'(x) is dy/dx.

So, our derivative is:

=\frac{dy}{dx}\sin(y)+y(\cos(y)\cdot\frac{dy}{dx}})

Simplify:

=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}

And we are done for the right.

Right Side:

We have:

\frac{d}{dx}[x\cos(x)]

This will be significantly easier since it's just x like normal.

Again, let's use the product rule:

=\frac{d}{dx}[x]\cos(x)+x\frac{d}{dx}[\cos(x)]

Differentiate:

=\cos(x)-x\sin(x)

So, our entire equation is:

=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}=\cos(x)-x\sin(x)

To find our derivative, we need to solve for dy/dx. So, let's factor out a dy/dx from the left. This yields:

\frac{dy}{dx}(\sin(y)+y\cos(y))=\cos(x)-x\sin(x)

Finally, divide everything by the expression inside the parentheses to obtain our derivative:

\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}

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5 0
2 years ago
Explain how to solve the equation and then check the solution.<br><br> 9 = q – 4
Vika [28.1K]

Assignment: \bold{Solve \ And \ Check \ Equation: \ 9=q-4}

<><><><><><><>

Answer: \boxed{\bold{q=13}}

<><><><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><><><>

[ Step One ] Switch Sides

\bold{q-4=9}

[ Step Two ] Add 4 To Both Sides

\bold{q-4+4=9+4}

[ Step Three ] Simplify

\bold{q=13}

[ Step Four ] Check Your Work

\bold{13 \ - \ 4 \ = \ 9}

[ Step Five ] Question: Is Equation Correct

\bold{Equation \ Is \ Correct, \ Therefore \ q=13}

<><><><><><><>

\bold{\rightarrow Mordancy \leftarrow}

5 0
3 years ago
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