Answer:
The correct options are 1, 4 and 6.
Step-by-step explanation:
From the given dot plots it is clear that the data set are:
Set 1: 1,1,1,1,1,2,2,2,2,2,2,2,2,3,3,3,4,4,7
Set 2: 1,1,1,1,1,2,2,2,2,2,2,2,2,3,3,3,4,4
Formula for mean:
![Mean=\frac{\sum x}{n}](https://tex.z-dn.net/?f=Mean%3D%5Cfrac%7B%5Csum%20x%7D%7Bn%7D)
![Mean_1=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4+7}{19}\apprxo 2.368](https://tex.z-dn.net/?f=Mean_1%3D%5Cfrac%7B1%2B1%2B1%2B1%2B1%2B2%2B2%2B2%2B2%2B2%2B2%2B2%2B2%2B3%2B3%2B3%2B4%2B4%2B7%7D%7B19%7D%5Capprxo%202.368)
![Mean_2=\frac{1+1+1+1+1+2+2+2+2+2+2+2+2+3+3+3+4+4}{18}\apprxo 2.111](https://tex.z-dn.net/?f=Mean_2%3D%5Cfrac%7B1%2B1%2B1%2B1%2B1%2B2%2B2%2B2%2B2%2B2%2B2%2B2%2B2%2B3%2B3%2B3%2B4%2B4%7D%7B18%7D%5Capprxo%202.111)
Mean of data set 1 is greater than mean of data set 2. Therefore option 1 is correct.
Set 1: (1,1,1,1,1,2,2,2,2),2,(2,2,2,3,3,3,4,4,7)
Set 2: (1,1,1,1,1,2,2,2,2),(2,2,2,2,3,3,3,4,4)
Median of both data sets is 2. Therefore option 4 is correct.
All data values of set 1 and set 2 are same except one value of data set 1, i.e. 7. The data set 1 is more spread than data set 2, therefore the standard deviation of data set 1 is greater. Option 5 is incorrect.
Set 1: (1,1,1,1),1,(2,2,2,2),2,(2,2,2,3),3,(3,4,4,7)
![Q_1=1,Q_3=3](https://tex.z-dn.net/?f=Q_1%3D1%2CQ_3%3D3)
![IQR_1=Q_3-Q_1=3-1=2](https://tex.z-dn.net/?f=IQR_1%3DQ_3-Q_1%3D3-1%3D2)
Set 2: (1,1,1,1),1,(2,2,2,2),(2,2,2,2),3,(3,3,4,4)
![Q_1=1,Q_3=3](https://tex.z-dn.net/?f=Q_1%3D1%2CQ_3%3D3)
![IQR_2=Q_3-Q_1=3-1=2](https://tex.z-dn.net/?f=IQR_2%3DQ_3-Q_1%3D3-1%3D2)
The data sets have the same IQR. Option 6 is correct.
Therefore the correct options are 1, 4 and 6.