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Alina [70]
3 years ago
11

What is the probability that from a normal 52 card deck, you randomly draw a 5, and then without replacement, you select a Queen

of Hearts?
Mathematics
1 answer:
Mamont248 [21]3 years ago
6 0

Answer:

1 / 663

Step-by-step explanation:

First, let's find the total number of ways you can pick 2 cards from the deck. This is 52 * 51 = 2652 because there are 52 cards available for your first pick, and after you pick one, you'll have 51 left for your second pick.

There are 4 5's  (one for every suite) and only 1 Queen of Hearts in a deck of cards. Therefore, the total number of successful outcomes will be 4 * 1 = 4.

The probability of picking a 5 and then a Queen of Hearts is 4 / 2652 =

1 / 663. Hope this helps!

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Give the set of four quantum numbers that represent the last electron added (using the aufbau principle to the cl atom.
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An element has four quantum numbers associated with it. We have

1. principal quantum number (n)
2. azimuthal quantum number (l)
3. magnetic quantum number (m_{l})
4. spin quantum number (m_{s})

To look for each quantum  number of Chlorine (Cl), we mus first recall its electronic configuration: 1s^{2}2s^{2}2p^{6}3s^{2}3p^{5}.

1. For n, we need to look for its highest energy level or by simply checking the period that the element belongs to. So for this case, it's n = 3.

2. For l, we need to look for the sublevel where the last electron was assigned. The sublevels, p, d, f are assigned to a value of 0, 1, 2, and 3, respectively. Since the last electron was assigned in p, then l = 1.

3. And for m_{l}, the number of orbitals present in Cl is 2l+1 = 3. The possible magnetic quantum numbers for p are -1, 0, +1. Since there 5 electrons we count starting at -1. So, we have m_{l}=+1[tex].\\4.  Lastly, for [tex]m_{s}, we need to determine the spin. Since we have 5 electrons, all the arrows upward are filled in. That means the fifth electron has a spin of +1/2. 

Answers: n =3, l = 1, m_{l} = 0, m_{s} =+1/2


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