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Alina [70]
3 years ago
11

What is the probability that from a normal 52 card deck, you randomly draw a 5, and then without replacement, you select a Queen

of Hearts?
Mathematics
1 answer:
Mamont248 [21]3 years ago
6 0

Answer:

1 / 663

Step-by-step explanation:

First, let's find the total number of ways you can pick 2 cards from the deck. This is 52 * 51 = 2652 because there are 52 cards available for your first pick, and after you pick one, you'll have 51 left for your second pick.

There are 4 5's  (one for every suite) and only 1 Queen of Hearts in a deck of cards. Therefore, the total number of successful outcomes will be 4 * 1 = 4.

The probability of picking a 5 and then a Queen of Hearts is 4 / 2652 =

1 / 663. Hope this helps!

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Preston is 8 years less than twice as many years old as tyler. If tyler is 12 years old, how old is preston
tia_tia [17]

Answer:

P=2T-8, if T=12, Preston, P=24-8=16 years old.

Hope this helps ;)

7 0
2 years ago
Read 2 more answers
In 1997 there were 31 laptop computers at grove high school. starting in 1998 the school bought 20 more laptop computers at the
Ksenya-84 [330]
We have equation:
t=20x+31
x is number of years after 1997.

To calculate number of laptops in 2005:
x=2005-1997
x=8

t=20*8+31
t=160+31
t=191

In year 2005 school had 191 laptops.
7 0
3 years ago
1 1/4ft = ______________ yd hurry!
Ymorist [56]

Answer:

4

Step-by-step explanation:

6 0
3 years ago
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Radioactive Decay Beginning with 16 grams of a radioactive element whose half -life is 30 years ,the mass y(in grams) remaining
Flura [38]

Answer:

the equation should be corrected to fit the data of the problem.  With the corrected equation a mass of 0.5 grams remains after 150 years

Step-by-step explanation:

for the mass y( in grams)

y=23* (1/2)^(t/45), t ≥ 0.

the initial mass is at t=0 , then

y= 23 grams  → should be 16 grams

half-life from the equation = 45 years → should be 30 years

the correct equation should be

y=16*(1/2)^(t/30), t ≥ 0

then after 150 years  → t= 150

y=16*(1/2)^(150/30)= 16*(1/2)^5 = 16/32 = 0.5 grams

then a mass of 0.5 grams remains after 150 years

5 0
3 years ago
I’m trying to find the answer for these 2 questions. Please!
Elanso [62]

1) For the second semester, we recognize that the number of actual students (75) is 15 times the ratio number (5) used to represent it. We also recognize that the total number of ratio units (5+4) for the second semester is the same as the total number (2+7) for the first semester.

If each ratio unit reprsents 15 students, in the first semester there were

... 2×15 = 30 students in art

... 7×15 = 105 students in gym

2) We can use the same sort of logic for the second problem as for the first. 6 ratio units represents $936 before money is moved, so each represents $156.

After the move, the account balances are

... savings: 4×$156 = $624

... checking: 3×$156 = $468

_____

Since the numbers of "ratio units" add to the same value in each case for both problems, we can solve this the way we have done—by determining the value a "ratio unit" stands for. If the problem had been posed differently, we might have been required to find the total number of students (dollars), then reapportion them according to the new ratios.

Essentially, when you have

... part1 : part2

you can find the total from

... part1 : total = part1 : (part1 + part2)

or

... (part1 + part2)/(part 1) × (actual value of part 1) = (actual value of total)

4 0
3 years ago
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