<h3>
Answer:</h3>
128.94 g/mol
<h3>
Explanation:</h3>
Given;
Mass of diprotic acid, H₂X =0.352 g
Molarity of NaOH = 0.150 M
Volume of the NaOH = 36.4 mL
We are required to calculate the molar mass of the acid.
Note: A diprotic acid is an acid that contains 2 replaceable hydrogen atoms
<h3>Step 1: Write the balanced equation fro the reaction;</h3>
The balanced equation for the reaction between the diprotic acid and NaOH will be;
H₂X(aq) + 2NaOH(aq) → Na₂X(aq) + 2H₂O(l)
<h3>Step 2: Determine the number of moles of NaOH used </h3>
Given the molarity and volume of NaOH we can calculate the number of moles;
Moles of NaOH = Molarity × Volume
= 0.150 M × 0.0364 L
= 0.00546 moles
<h3>Step 3: Use the mole ratio to determine moles of the acid </h3>
From the equation;
1 mole of the acid reacts with 2 moles of NaOH
Therefore; H₂x : NaOH = 1 : 2
Moles of H₂x = 0.00546 moles ÷ 2
= 0.00273 moles
<h3>Step 4: Determine the molar mass of the acid.</h3>
Molar mass is the mass equivalent to 1 mole of a compound or element
From our calculations;
0.00273 moles = 0.352 g of the acid;
Therefore, mass in 1 mole ;
= 0.352 g ÷ 0.00273 moles
= 128.94 g/mol
Thus, the molar mass of the diprotic, H₂X is 128.94 g/mol
