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2 years ago

If a compound has a molar más of 180g/mol and it’s empirical formula is CH^2O, what is it’s molecular formula?

Chemistry

1 answer:

lesya [120]2 years ago

4 0

C: 12.0107 g/mol ≅ 12.00 g/mol

H: 1.00784 g/mol ≅ 1.008 g/mol

O: 15.999 g/mol ≅ 16.00 g/mol

n(molar mass of CH2O)= 180

n.30=180

n=6

molecular formula: c6h12o6 glucose

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Now, calculating the theoretical yield of iron (ii) oxide using equation 1, we get:

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To calculate the percentage yield of iron (ii) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

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Theoretical yield of iron (ii) oxide = 5.53 g

Putting values in above equation, we get:

$\%\text{ yield of iron (ii) oxide}=\frac{5.17g}{5.53g}\times 100\\\\\% \text{yield of iron (ii) oxide}=93.49\%$

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