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hichkok12 [17]
3 years ago
8

Which yields H+(aq) as the only positive ion in an aqueous solution?(1) CH3CHO (2) CH3CH2OH (3) CH3COOH (4) CH3OCH3

Chemistry
2 answers:
ioda3 years ago
7 0

Answer:The correct answer is option (3).

Explanation:

Carboxylic acid gives H^+ ions in their aqueous solution.

RCOOH\rightleftharpoons RCOO^-+H^+

CH_3COOH\rightleftharpoons CH_3COO^-+H^+

Carbonate ion formed is stabilized due to resonance.

Whereas aldehyde in their aqueous solution do not give H^+ions.

Alcohol in their aqueous solution do not give H^+ions.

Ether in their aqueous solution do not give H^+ions.

Arte-miy333 [17]3 years ago
5 0
If H+ would have to dissociate from a substance and must be the only positive ion in the solution that substance must be an acid.
CH3CHO is an aldehyde called acetaldehyde. 
CH3CH2OH is an alcohol called ethanol 
CH3OCH3 is an ether called dimethyl ether. 
and finally, the answer CH3COOH is a weak acid called acetic acid. 
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Bas_tet [7]

Answer:

9.3x10^{26}molec\ I_2

Explanation:

Hello!

In this case, considering the balanced chemical reaction:

Cl₂ + 2LiI ⇒ 2LiCl + I₂

We can see there is a 1:1 mole ratio between the produced iodine and the used chlorine, thus, we infer that the number of molecules of iodine given those of chlorine turn out:

9.3x10^{26}molec\ Cl_2*\frac{6.022x10^{23}molec\ I_2}{6.022x10^{23}molec\ Cl_2} =9.3x10^{26}molec\ I_2

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8 0
3 years ago
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gA scientist is trying to discover information about an unknown metal in a compound. The formula for the compound is believed to
Hitman42 [59]

Solution :

It is given that :

The formula of the compound = $XBr_3$

And that 4.70 g of the sample contains $4.834 \times 10^{-2}$ mol of Br.

It means that :

1 mol of $XBr_3$ contains = 3 mol of Br

∴ 3 mol of $Br^-$ contain in 1 mol of $XBr_3$

$4.834 \times 10^{-2}$ mol of $Br^-$  contains $1.576 \times 10^{-2}$ mol of $XBr_3$

Thus the mol of $XBr_3$ = $1.576 \times 10^{-2}$ mol

The given mass is = 4.700 g

Therefore, the $\text{molar mass}$ of $XBr_3$  $=\frac{\text{mass}}{\text{mol}}$

                                                           $=\frac{4.700 \ g}{1.576 \times 10^{-2} \ mol}$

                                                          = 298.4 g/mol

So $\text{molar mass}$ of $XBr_3$ = $\text{molar mass}$ of X + 3 x $\text{molar mass}$ of Br

      298.4 g/mol = $\text{molar mass}$ of X + 3 x 79.90 g/mol

      298.4 g/mol = $\text{molar mass}$ of X + 239.7 g/mol

       $\text{molar mass}$ of X = 58.71 g/mol    (since 1 amu = 1 g/mol)      

Therefore the atomic mass of the unknown metal = 58.71 g/mol

So the unknown meta is Nickel.

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