A. As you make more and more of one good or service, you will also make more and more of another.
Here we have to get the amount of propane can be produced from the reaction of 1.7 moles of carbon (C).
1.7 moles of carbon will produce 0.425 moles of propane
In the reaction 8 moles of carbon is producing 2 moles of propane. Thus, mathematically,
8C → 2C₃H₈
Thus 8 moles of carbon produces 2 moles of propane
1.7 moles of carbon produces ×1.7 = 0.425 moles
Thus 1.7 moles of carbon will produce 0.425 moles of propane.
Thus the amount of propane will be prepared from the reaction of 1.7 moles of carbon is determined.
Answer:
3.5 atm
Explanation:
Given data
- Initial pressure (P₁): 47.9 atm
- Initial volume (V₁): 21 L
We can find the maximum pressure that the gas can exert (final pressure) using Boyle´s law.
P₁ × V₁ = P₂ × V₂
P₂ = P₁ × V₁ / V₂
P₂ = 47.9 atm × 21 L / 290 L
P₂ = 3.5 atm
Moles= mass divided by Molecular mass
Moles= 251.4 divided by 84
Moles=2.99
Rounded up is 3