H2O is the Bronsted-Lowry base because it accepts the hydrogen ion to become H3O after the reaction is complete.
its me again this is how you find the answer. note: i dont have the periodic table to see the exact atomic mass to find the molar mass however this is the answer:
so the actual formula is Mg(OH) with a 2 as a subscript because there are 2 Mg. so with Mg(OH)2 the Molar mass is 58.32g/mol. 58.32 g/mol x 7.1x1024 = 4.1x1026g
Answer:
9.01%
Explanation:
The following data were obtained from the question:
Mass of sodium nitrate, NaNO3 = 56.5g
Mass of solution = 627g
The percentage composition of sodium nitrate, NaNO3 in the solution can be obtained as follow:
Percentage composition of NaNO3 = Mass of NaNO3/mass of solution x 100
Percentage composition of NaNO3 = 56.5/627 x 100 = 9.01%
Therefore, the percentage composition of sodium nitrate, NaNO3 in the solution is 9.01%
Answer:
Hi there!
I believe you are missing an attachment to this question however
I strongly believe that the answer you are looking for is 85.
Explanation:
If you provide the graph, the rate of strokes in Asian women will be 17 per 1,000 women so all you have to do is multiply 17 by 5 and you get 85
Hey there !
Molecular Weight: 262.86 g/mol
Volume in liters : 1,000 mL => 1,000 / 1000 => 1 L
Number of moles of solution :
number of moles = volume x molarity
number of moles = 1 x 0.3 => 0.3 moles
Therefore:
1 mole Mg₃(PO₄)₂ ------------------- 262.86 g
0.3 moles ----------------------------- mass of Mg₃(PO₄)₂ ??
mass of Mg₃(PO₄)₂ = 0.3 x 262.86 / 1
mass of Mg(PO₄)₂ => 78.858 g
Hope this helps!