Given,
Cylinder A has a volume of 6 cubic units
and height =3 units
The radius of cylinder A,
![\begin{gathered} r=\sqrt[]{\frac{V}{\pi h}} \\ =\sqrt[]{\frac{6}{3\pi}} \\ =0.8 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20r%3D%5Csqrt%5B%5D%7B%5Cfrac%7BV%7D%7B%5Cpi%20h%7D%7D%20%5C%5C%20%3D%5Csqrt%5B%5D%7B%5Cfrac%7B6%7D%7B3%5Cpi%7D%7D%20%5C%5C%20%3D0.8%20%5Cend%7Bgathered%7D)
To find the volume of a cylinder B
Thus the volume of cylinder B is 6.03
Answer:
Step-by-step explanation:
Perimeter of a rectangle = 2(L +W)
Given L = W + 2 and the perimeter is greater than 112 meters?
P rect < 2(L +W) L = W + 2
P rect < 2(W + 2 +W)
< 2(2W+2)
112 < 4W + 4 solve for W
(112 - 4)/4 < (4W +4 - 4)/4
108/4 < (4W + 0)/4
27 < W
the width has to be greater than 27 meters
Answer:
0=19
Step-by-step explanation:
Answer:
48
Step-by-step explanation:
1.5
x 32
The formula for gravitational force F is equal to the gravitational constant multiplied by the respective masses of both objects, all over the square of the distance between the two. In mathematical form:
Let:
G = gravitational constant
M = mass of one object
m = mass of the other object
d = distance between the two objects
F = gravitational force
F = (G * M * m) / d^2
As seen in the formula, the gravitational force or force of attraction is inversely proportional to the square of the distance. If we were to increase the distance by 4 times as much, this would reduce the force of attraction by 16 times.
