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suter [353]
2 years ago
11

Solve for x. enter your answer in interval notion using grouping symbols. x^2+2x<15

Mathematics
1 answer:
bezimeni [28]2 years ago
5 0

The inequality would be -5<x<3...

Hope this helps!

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Can someone help me with this.?
prohojiy [21]

Answer:

Below.

Step-by-step explanation:

To find the answer, you have to compare the two equations:

y=\frac{1}{10}x+60 and y=\frac{1}{5}

So first, the graph looks different because the two slopes are different. The first one will be more vertical than the second one.

The second difference is the y - intercepts. The first equation starts at (0, 60) and the second starts at the origin.

4 0
3 years ago
The temperature at a ski resort was 12°F at 5:00 A.M. If the temperature increased by 1.5°F each hour, what would be the tempera
Mariana [72]

The <em><u>correct answer</u></em> is:

22.5° F.

Explanation:

The temperature increases 1.5° per hour.  From 5:00 AM to 12:00 PM is 12-5 = 7 hours.  This makes an increase of 1.5(7) = 10.5°.

The temperature started at 12°F; increasing by 10.5° gives us

12+10.5 = 22.5°F.

3 0
2 years ago
How long should a person take to travel 2000m at an average speed of 5m/s
zimovet [89]

Answer:

400

Step-by-step explanation:

8 0
2 years ago
a ship leave port p and sails on a bearing N50 degree E to Port Q 15km away.then it sails on a bearing of S45 degree E to Port R
Shtirlitz [24]

Answer:

Port r is 100° from Port p and 26km from Port p

Step-by-step explanation:

Lets note the dimension.

From p to q = 15 km = a

From q to r = 20 km= b

Angle at q = 50° + 45°

Angle at q = 95°

Ley the unknown distance be x

Distance from p to r is the unknown.

The formula to be applied is

X²= a²+ b² - 2abcosx

X²= 15² + 20² - 2(15)(20)cos95

X²= 225+400-(-52.29)

X²= 677.29

X= 26.02

X is approximately 26 km

To know it's direction from p

20/sin p = 26/sin 95

Sin p= 20/26 * sin 95

Sin p = 0.7663

P= 50°

So port r is (50+50)° from Port p

And 26 km far from p

3 0
3 years ago
Jason and Britton are driving to St. George. Jason got a 20 mile head start and drove an
harina [27]

Answer:

  2 hours, 150 miles

Step-by-step explanation:

The relation between time, speed, and distance can be used to solve this problem. It can work well to consider just the distance between the drivers, and the speed at which that is changing.

<h3>Separation distance</h3>

Jason got a head start of 20 miles, so that is the initial separation between the two drivers.

<h3>Closure speed</h3>

Jason is driving 10 mph faster than Britton, so is closing the initial separation gap at that rate.

<h3>Closure time</h3>

The relevant relation is ...

  time = distance/speed

Then the time it takes to reduce the separation distance to zero is ...

  closure time = separation distance / closure speed = 20 mi / (10 mi/h)

  closure time = 2 h

Britton will catch up to Jason after 2 hours. In that time, Britton will have driven (2 h)(75 mi/h) = 150 miles.

__

<em>Additional comment</em>

The attached graph shows the distance driven as a function of time from when Britton started. The distances will be equal after 2 hours, meaning the drivers are in the same place, 150 miles from their starting spot.

3 0
1 year ago
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