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julia-pushkina [17]
4 years ago
8

What is the domain of the graph

Mathematics
1 answer:
Murrr4er [49]4 years ago
7 0

All the input values shown on the x-axis

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Please help with this math question!
Ulleksa [173]

Answer:

Step-by-step explanation:

C

5 0
3 years ago
bricks having volume 500cm^3 each are selected to construct a compound wall of 200m×0.5m×1.5.If theprice of the brick is Rs.14,f
maria [59]

Answer:

Rs. 4,200,000

Step-by-step explanation:

Given :

Volume of brick = 500cm³

Dimension of wall : 200m×0.5m×1.5m

Converting to cm

Volume of compound wall:

(200 * 100) * (0.5 * 100) * (1.5 * 100)

20000cm * 50cm * 150cm=

= 150000000cm³

Volume of compound wall / volume of brick

1500000000 cm³ / 500 cm³

= 300000

Price per brick = Rs. 14

Total price = 14 * 300000 = Rs. 4,200,000

4 0
3 years ago
HELPPPPPPP 40 POINTS... ITS ONE QUESTION. 40 POINTS AND BRAINLIEST.. FIND X THERE IS ONE IMAGE
morpeh [17]

Answer:

  • x = 19

Step-by-step explanation:

<u>Use ratios:</u>

  • 30/20 = (x + 5)/(36 - 20)
  • 3/2 = (x + 5)/16
  • 2(x + 5) = 3(16)
  • 2x + 10 = 48
  • 2x = 38
  • x = 19
4 0
3 years ago
Read 2 more answers
Manchester Community College
frozen [14]

Answer:

1/3

Step-by-step explanation: im a young fellow im not sure

7 0
4 years ago
Consider functions f and g
alexdok [17]

Answer:

A

Step-by-step explanation:

f(x) = \dfrac{x - 16}{x^2 + 6x - 40}

g(x) = \dfrac{1}{x + 10}

f(x) + g(x) =  \dfrac{x - 16}{x^2 + 6x - 40} + \dfrac{1}{x + 10}

f(x) + g(x) =  \dfrac{x - 16}{x^2 + 6x - 40} + \dfrac{(x - 4)}{(x + 10)(x - 4)}

f(x) + g(x) =  \dfrac{x - 16 + x - 4}{x^2 + 6x - 40}

f(x) + g(x) =  \dfrac{2x - 20}{x^2 + 6x - 40}

Answer: A

6 0
2 years ago
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