7.5 meters
Don’t need to use 980j if you use the correct equations
Answer:
a. verify that your observations are correct
c. think about what else might cause the observed discrepancy
Explanation:
Let's begin by explaining that a law is an affirmation (something established) based on repeated long-term observation of a phenomenon that has been studied and verified.
That is: A law is present in all known theories and therefore is considered universal. In addition, <u>a law can not be refuted, nor changed, because its precepts have been proven through various studies.</u>
Then, based on what is explained above, Kepler's laws of planetary motion exist because they were rigorously tested and verified, therefore they can not be refuted.
So, if we have a small discrepancy between the predicted and actual positions of Uranus after using Kepler's laws, we have to verify carefully our observations again and search what might be causing that discrepancy. But we cannot assume Kepler's Laws are incorrecto or need modifications.
In addition, we cannot consider that Uranus may not be a planet, because the discrepancy is small. In fact, this discrepancy lead to the discovery of another planet, Neptune.
Explanation:
Vi = 12 m/s
a = 3 m/s^2
t = 2 s
Vf = Vi + a × t = 12 + 3 ×2 = 18 m/s
Answer:
C
Explanation:
Rt= total resistance
we know that 1/Rt=1/R1+1/R2(from ohm's law)
Since, Rt=4 and R1=R2
we will get,
1/4=2/R2
R2=8
when in series Rt=R1+R2,
So, Rt=8+8=16 ohm's
<h2>Answer: 10.52m</h2><h2 />
First, we have to establish the <u>reference system</u>. Let's assume that the building is on the negative y-axis and that the brick was thrown at the origin (see figure attached).
According to this, the initial velocity
has two components, because the brick was thrown at an angle
:
(1)
(2)
(3)
(4)
As this is a projectile motion, we have two principal equations related:
<h2>
In the x-axis:
</h2>
(5)
Where:
is the distance where the brick landed
is the time in seconds
If we already know
and
, we have to find the time (we will need it for the following equation):
(6)
(7)
<h2>
In the y-axis:
</h2>
(8)
Where:
is the height of the building (<u>in this case it has a negative sign because of the reference system we chose)</u>
is the acceleration due gravity
Substituting the known values, including the time we found on equation (7) in equation (8), we will find the height of the building:
(9)
(10)
Multiplying by -1 each side of the equation:
>>>>This is the height of the building